The ratio of secondary turns to primary turns in a transformer is 37 to 4. How many secondary turns are there if the primary coi
1 answer:
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Answer:
xbar=14.3421
s=18.7920
Step-by-step explanation:
sample mean
xbar = ∑x/n = (0.20 + 0.73 + 0.99 +1.29 + 2.84 + 3.34 + 4.07 + 4.69 + 4.86 + 6.53 + 7.45 + 8.07 + 8.21 + 12.39 + 31.67 + 32.53 + 33.92 + 36.00 +72.72)/19=14.3421
where n stands for the size of the sample
sample deviation
s= (∑
/(n-1)) =
(∑
-
)/(n-1)) =
(0.20^2 + 0.73^2 + 0.99^2 +1.29^2 + 2.84^2 + 3.34^2 + 4.07^2 + 4.69^2 + 4.86^2 + 6.53^2 + 7.45^2 + 8.07^2 + 8.21^2 + 12.39^2 + 31.67 ^2+ 32.53^2 + 33.92^2 + 36.00^2 +72.72^2-19*14.3421^2)/(19-1)) = 18.7920