Answer:
Number of nucleosomes in
bp is equal to 
Explanation:
For wounding one nucleosome, total length of DNA required is equal to
bp
The length of linker DNA in mammals is equal to
bp
Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length
bp
Thus, in
bp length of DNA, the total number of nucleosomes is equal to 
Thus, number of nucleosomes in
bp is equal to

Answer: 8hrs
Explanation:
G1 phase is the intermediate phase between the end if cell division and the beginning of DNA replication.
Thus to get the duration of the G1 phase = 1/3 × 24hrs = 8hrs
Answer:
only females
Explanation:
In humans, sex chromosomes in males and females are different. The sex chromosomes found in humans are X and Y chromosomes. X-linked trait is a trait which is inherited on the X- chromosome. According to the question, the trait is passed on a X-linked dominant condition, which means the condition is inherited on the abnormal dominant X-chromosome that will express itself even when in an heterozygous state with a normal X-chromosome.
Hence, a father affected by the condition will have a genotype; XY while a mother that does not have the condition will have a genotype: xx (two normal x chromosomes). Since the Father can only pass his X chromosome to his daughters and never his sons, all his daughters will inherit the condition (see the punnet square in attached image).
N.B: None of the sons will inherit the condition since the mother will pass normal X-chromosomes (x) to her sons.