Answer:
Given,
ABC is triangle with vertices A(-2,1), B(2,2) and C(6, -2)
Slope of BC(m_1) =
Since AD is perpendicular to BC
let slope of BC be (
).
We have for perpendicular
Now equation of line passing through point A(-2,1) is
y-1=1(x-(-2))
y-1=x+2
y=x+2+1
y=x+3 which is a required equation of the altitude of AD drawn from A to BC.
Answer:
b = 0.
Step-by-step explanation:
The only value for b that makes the equation true is 0. So, the equation has a unique solution of b = 0.
Answer:
x=3 y=-1
Step-by-step explanation:
To get the value of x you need to put in the second equation which is y=8-3x as the y value for the first equation which is 2x+3y=3 making it
2x+3(8-3x)=3
2x+24-9x =3
24-7x =3
-7x=-21
Multiplying both sides by -7
x= 3
After getting an x value you substitute it in the equation in order to find your y value which is
2x+3y=3
2(3)+3y=3
3y=-3
Multiplying both sides by 3
y= <u>-3</u>
3
y=-1
That is true. when a point lies on the x-axis, the y-coordinate is 0.
Answer:
a(x+y+z)
Step-by-step explanation:
Since there is an "A" in each term we can divide "A" in all the terms to get a(x+y+z).
