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Annette [7]
2 years ago
9

Please help will give brainlist

Mathematics
2 answers:
RoseWind [281]2 years ago
6 0
6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. These are the zeroes.
katovenus [111]2 years ago
5 0
<h2>Answer:</h2>

The zeros of the quadratic function f(x) are:

    D.\ x=2+\sqrt{\dfrac{23}{6}},\ x=2-\sqrt{\dfrac{23}{6}}

<h2>Step-by-step explanation:</h2>

We are given a quadratic function in terms of x as:

                f(x)=6x^2-24x+1

We know that any quadratic function of the type:

ax^2+bx+c=0

has solution as:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here we are asked to find the zeros of the function f(x) i.e.

we are asked to find x such that:

f(x)=0

i.e.

6x^2-24x+1=0

i.e. here a=6,\ b=-24\ and\ c=1

Hence, we have the solution as:

x=\dfrac{-(-24)\pm \sqrt{(-24)^2-4\times 6\times 1}}{2\times 6}\\\\i.e.\\\\x=\dfrac{24\pm \sqrt{576-24}}{12}\\\\i.e.\\\\x=\dfrac{24\pm \sqrt{552}}{12}\\\\i.e.\\\\x=\dfrac{24\pm 2\sqrt{138}}{12}\\\\i.e.\\\\x=\dfrac{24}{12}\pm \dfrac{2\sqrt{138}}{12}\\\\i.e.\\\\x=2\pm \dfrac{\sqrt{138}}{6}\\\\i.e.\\\\x=2\pm \sqrt{\dfrac{138}{36}}\\\\i.e.\\\\x=2\pm \sqrt{\dfrac{23}{6}}\\\\i.e.\\\\x=2+\sqrt{\dfrac{23}{6}},\ x=2-\sqrt{\dfrac{23}{6}}

  <em>       The correct answer is: Option : D</em>

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76

Step-by-step explanation:

so the sequence(pattern) is it increases by 5

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In triangle ABC, line A.B.=CB Angle ABC equals 4X -3, and angle CAB equals X -3, what is angle ACB
Soloha48 [4]

Answer:

∠ACB = 28.5

Step-by-step explanation:

In triangle ABC,

angle CAB = x-3

angle ABC = 4X-3

It is also given that AB=CB

We know that if two sides of any triangle are equal then corresponding sides must also be equal.

Hence

angle ACB = angle CAB

angle ACB = x-3    {Given that angle CAB = x-3 }

We know that sum of all three angles of a triangle is 180 degree so let's add given angles

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3 0
3 years ago
What are the real solutions of x squared =225
Gnesinka [82]

The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.

<h3>What are the real solutions of the equation as given in the task content?</h3>

It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;

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Therefore, the real solutions of the equation are; +25 and -25.

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A farmer market has 7/9 bushel of plums when it opens in the morning.By noon ,1/3of the plums are left .How many ,plums in bushe
FromTheMoon [43]

Answer:

farmers market sold 4/9 plums in bushel

Step-by-step explanation:

We know that at the beginning of the day we have 7/9 of a bushel of plums and that after a while there are 1/3 of a bushel of plums, so to calculate how many were sold we have to subtract the bushel of plums that were left from the initial ones

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