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dlinn [17]
3 years ago
8

For the data set below identify the interquartile range of the data.

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0

To find the range of a set, subtract the largest number and the smallest number. Those numbers, in this set, are 63 and 34.

63-34=29

So the range is 29

---

sorry if I didn't help

Dahasolnce [82]3 years ago
5 0
The answer would be 63-34=29.
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Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be 27.
padilas [110]

Answer:

78

Step-by-step explanation:

The IQR is quartile 3 - quartile 1. First, we need to find the mean of the dataset, which is 50 -- the fifth number. Then, the median of the dataset on the left of the fifth number is the first quartile, and the median of the dataset on the right is the third. We get Q1 to then be halfway between 30 and 50, or 40, and Q3 to be halfway between 56 and n, so Q3 = (56+n)/2. Since we need Q3-Q1=27, or (56+n)/2-40=27, we have (56+n)/2=67 and 56+n=134, so n = 134-56=78

3 0
3 years ago
The sine and cosine of one of the acute angles in a right triangle are equal. What is the tangent of the angle?
Gnoma [55]

Answer:

1

Step-by-step explanation:

Since tan(x) = sin(x)/cos(x), if sin(x) = cos(x) then tan(x) must be 1.

You can even reason that the acute angle is 45° and sin(x)=cos(x) = \frac12\sqrt2.

4 0
3 years ago
Which shows the numbers in order from least to greatest?
gavmur [86]
So just convert to a common form
I will convert to decimal since 2 of them are already decimals

to conver 1 and 3/7 to decimal, just divide 3 by 7 using a calculator
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the greates is .43 then .40 then .38 so the order is
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1.38, 1.4, 1 3/7 or D
5 0
3 years ago
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12345 [234]

Answer:

The standard form of the quadratic equation is x² + 3·x - 4 = 0

Step-by-step explanation:

The standard form of a quadratic equation is a·x² + b·x + c = 0

Given that the expression of the quadratic equation is (x + 4)·(x - 1) = y, we can write the given expression in standard form by expanding, and equating the result to zero as follows;

(x + 4)·(x - 1) = x² - x + 4·x - 4 = x² + 3·x - 4 = 0

The standard form of the quadratic equation is x² + 3·x - 4 = 0

The graph of the equation created with MS Excel is attached

4 0
3 years ago
Find the solution for 6x+3y=3 3x-y=4​
Mariana [72]
I think the answer is 7x
5 0
3 years ago
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