Answer:
this four sections are called the quadrants
Answer:
cost of a box is $3.5
Step-by-step explanation:
given data
sold box = 18
earned = $136.50
solution
we consider here number of boxes of cookies is x
and
for we get Tyler sold cookies box so number of boxes we divide 702 cookies among 18 is
Tyler sold = 
Tyler sold = 39 boxes
and
now we consider here y as cost of each box of cookies,
so for cost or sale price of the cookie boxes here we divided 136.50 dollars among 39 boxes
so
cost of each box = 
cost of each box = 3.5
Thus, the cost of each box was 3.5
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
Answer:
The upper endpoint of the 99% confidence interval for population proportion is 0.13.
Step-by-step explanation:
The confidence interval for population proportion is:

<u>Given:</u>
<em>n</em> = 1000
= 0.102

*Use the standard normal table for the critical value.
Compute the 99% confidence interval for population proportion as follows:

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.