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3 years ago

What is the surface area of the cube?(please and put your answer as a number without a unit.)

Mathematics

1 answer:

Vikentia [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Total surface area of cube = a^3

here , a = 11 cm

So surface area of the cube = a^3

= 11^3

=1331 cm^3

Hope this helps

Plz mark it as brainliest

You might be interested in

Write 0.0003532 in scientific notation.

tatyana61 [14]

The answer is.... 3.532*10^-4

8 0

3 years ago

Let f(x)=x^2-5x-36.

Georgia [21]

Answer:

9 and -4

Step-by-step explanation:

Find two numbers that multiply to be -36 and add to be -5.

That is -9 and 4.

So the factored form of x^2-5x-36 is (x-9)(x+4)

So the x-intercepts are 9 and -4

8 0

3 years ago

Dylan is evaluating the expression 13 + 19 + 7 + 10. At one step in his work, Dylan rewrites the equation as 13 + 7 + 19 + 10. W

AlekseyPX

Answer:

Communicative Property

Step-by-step explanation:

The communicative property is basically just switching numbers around but still leading to the same answer, if you could see, both of the equations lead to the same answer, 49. Here is a chart to help you out.

7 0

3 years ago

What is the range for this set of data? 7, 15, 12Mrs. Juarez graded ten English papers and recorded the scores. 92, 95, 100, 62,

ra1l [238]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

Arrange the value into the ascending order:

$62, 88, 89, 90, 92, 95, 96, 98, 100, 100$

Calculating the Range:

$= Greatest - Lowest\\\\= 100 - 62\\\\ = 38$

Outlier = This might be the value "far" from other data values= 62

The range of scores would be, sans outlier,

$88, 89, 90, 92, 95, 96, 98, 100, 100$

Calculating the range without outlier $= 100 - 88 = 12$

Inter Quartile Range $= Q_3 - Q_1$

$IQR = 98 - 89 = 11$

Calculating the IQR without outlier $= 99 - 89.5 = 9.5$

Therefore,

Option a is "True".

Option b is "True".

Option c is "True".

Option d is "False".

Option e is "False".

Option f is "True".

5 0

2 years ago

A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi

Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

Let X = number of names recalled

SO, X ~ N( $\mu = 19.41,\sigma^{2} = 3.17^{2}$ )

The z-score probability distribution is given by ;

Z = $\frac{X-\mu}{\sigma} } }$ ~ N(0,1)

where, $\mu$ = mean number of names recalled = 19.41

$\sigma$ = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

P(X > 15) = P( $\frac{X-\mu}{{\sigma} } }$ > $\frac{15-19.41}{3.17} }$ ) = P(Z > -1.39)

= P(Z < 1.39) = 0.9177 {using z table}

Therefore, proportion of the students recalled more than 15 names is 91.77%.

4 0

3 years ago