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Sloan [31]
4 years ago
5

how many neutrons are present in each of the tree elments you idenitifed in your chosen type steel? be sure to show calculations

used arrive at answer
Chemistry
1 answer:
Alex_Xolod [135]4 years ago
5 0

Start with atomic mass subtract atomic number for each element to get neutrons for each element.

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Type the chemical name of the compound that contains 1 copper atom, 1 oxygen
Bas_tet [7]

Answer:

Copper (I) hydroxide

Explanation:

Copper (I) hydroxide is a chemical compound with the chemical formula of CuOH. One copper atom (Cu), one oxygen atom (O), and one hydrogen atom (H.)

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3 years ago
How do you study things that your not interested. Im studying about rocks and it isnt my type
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The heating curve below shows the temperature change that occurs as a solid is heated. What is occurring at segment BC of the gr
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9. Thallium-208 has a half-life of 3.053 min. How long will it take for 120 g of it to decay
damaskus [11]

Answer:

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

Explanation:

Radioactive isotopes decay exponentially in time, the mass of the isotope (m(t)), in grams, is described by the formula in time (t), in minutes:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

m_{o} - Initial mass of the isotope, in grams.

\tau - Time constant, in minutes.

In addition, the time constant associated with the isotope decay can be described in terms of half-life (t_{1/2}), in minutes:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m(t) = 7.5\,g, m_{o} = 120\,g and t_{1/2} = 3.053\,min, then the time taken by the isotope is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{3.053\,min}{\ln 2}

\tau \approx 4.405\,min

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(4.405\,min)\cdot \ln \left(\frac{7.5\,g}{120\,g} \right)

t \approx 12.213\,min

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

4 0
3 years ago
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