Answer:
8.33 atm
Explanation:
Xe is 5 out of (4+5) or 5 / 9 ths of the gas present
5/9 * 15 atm = 8.33 atm
Not necessarily.
<h3>Explanation</h3>
Isomers might differ in polarities. They will end up with different physical properties such as melting points.
Example:
- 1,2-dichlorobenzene has a melting point of around -18 ~ -17 degrees celsius. (SynQuest)
- 1,4-dichlorobenzene (with two chlorine opposite to each other on a benzene ring) has a melting point of 52 ~ 54 degrees celsius. (SynQuest)
Both 1,4- and 1,2-dichlorobenzene contains two chlorine atoms connected to a benzene ring. The two molecules are structural isomers.
The two chlorine atoms are adjacent to each other in the 1,2 isomer. The molecule is asymmetric and polar.
The two chlorine align with an axis of symmetry in the 1,4 isomer. The molecule is symmetric. The dipoles would cancel out to produce a nonpolar molecule.
Dipole-dipole interactions are typically stronger than <em>induced</em> dipole<em> </em>in isomers. As a result, the 1,2 isomer has a higher melting point.
Answer:
[HAc] = 0.05M
[Ac⁻] = 0.20M
Explanation:
The Henderson-Hasselbalch formula for the acetic acid buffer is:
pH = pka + log₁₀ [Ac⁻] / [HAc]
Replacing:
5.36 = 4.76 + log₁₀ [Ac⁻] / [HAc]
3.981 = [Ac⁻] / [HAc] <em>(1)</em>
Also, as total concentration of buffer is 0.25M it is possible to write:
0.25M = [Ac⁻] + [HAc] <em>(2)</em>
Replacing (2) in (1)
3.981 = 0.25M - [HAc] / [HAc]
3.981 [HAc] = 0.25M - [HAc]
4.981 [HAc] = 0.25M
<em>[HAc] = 0.05M</em>
Replacing this value in (2):
0.25M = [Ac⁻] + 0.05M
<em>[Ac⁻] = 0.20M</em>
I hope it helps!
Answer:
The Changes I see is the Hot glass have less air bubbles than the Cold Glass. The Cold Glass has more air bubbles than the Hot Glass.
I hope this helps. I tried my best!! Good Luck!!
The answer is 69.048%.
Mass of potassium dichromate (K₂Cr₂O₇) is 294 g, which is a 100%.
Given mass of chromium is 52 g. So, the mass percent of chromium in the compound is 17.687%:
52 g : x% = 294 g : 100%
x = 52 ÷ 294 × 100 %
x = 17.687%
Given mass of potassium is 39 g. <span>So, the mass percent of potassium in the compound is 13.265%:
39 g : x% = 294 g : 100%
x = </span>39 ÷ <span>294 × 100 %
x = 13.265%
Therefore, </span>the mass percent of oxygen in the compound is <span>69.048%:
100% - </span>17.687% - <span>13.265% = 69.048%.</span>
