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zloy xaker [14]
3 years ago
13

Use addition to solve the linear system of equations. Include all of your work in your final answer.

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

x=-12, y = 8

Step-by-step explanation:

-x-y=4

x+2y=4


Add these two equations together to eliminate x

-x-y=4

x+2y=4

-----------------

y=8

Now we need to find x

x+2y =4

Substitute y in

x +2(8) =4

x+16 =4

Subtract 16 from each side

x+16-16 =4-16

x=-12

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Jack is holding nickels and dimes. He has 4 more dimes than nickels. He has a total of $.70 in his hand. How many of each coin d
Alexxandr [17]
Sorry it is 2 nickel which equals ₵10 and 6 dimes which equals ₵60 and when you add them together they equal ₵70
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If f(x, y) = xy, find the gradient vector ∇f(2, 5) and use it to find the tangent line to the level curve f(x, y) = 10 at the po
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Answer:

Step-by-step explanation:

check attachment

f(x,y)=xy       Δf(2,5)

fx=y = 5

fy=x = 2

Gradient Vector:

<5,2>

Tangent Vector:

0=fx(x-2) + fy(y-5)

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3 years ago
The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds. A sampl
Westkost [7]

Answer:

1963.2 pounds (lbs.)

Step-by-step explanation:

Things to understand before solving:

  • - <u>Normal Probability Distribution</u>
  1. The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by: Z=\frac{X-u}{a}

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.

  • - <u>Central Limit Theorem</u>
  1. The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц  and standard deviation s=\frac{a}{\sqrt{n} }

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.

This means, ц  = 2000 and б = 100.

A random sample of 20 cables is chosen and tested.

This means that n = 20, s=\frac{100}{\sqrt{120} } =22.361

Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.

This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So Z=\frac{X-u}{a}

  • By the Central Limit Theorem

Z=\frac{X-u}{a} \\-1.645=\frac{X-2000}{22.361} \\X-2000=-1.645*22.361

X =1963.2

<h3>Answer:</h3>

The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.

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