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Anton [14]
3 years ago
5

How do you solve this? ASAP please help me. a^2+2.1^2=2.9

Mathematics
1 answer:
ss7ja [257]3 years ago
3 0
Convert decimal to fraction
a^2+(21/10)^2=2.9
Use exponent rules
a^2+441/100=2.9
Move constant to the right
a^2=2.9-441/100
Calculate
a^2=-151/100
This equation has no solution.
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Plz help been stuck on this for awhile
Kazeer [188]

Answer:

<em>d</em> = \sqrt{74}  or 8.60

Step-by-step explanation:

(5, 8) (-2, 3)

Let 5 = x_{1}

     8 = y_{1}

     -2 = x_{2}

     3 = y_{2}

Plug in the values into the equation to get the distance:

<em>d = </em>\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}    }<em />

<em>d </em>= \sqrt{(-2-5)^{2} + (3-8)^{2} }

<em>d = </em>\sqrt{(-7)^{2} + (5)^{2}  }

<em>d</em> =  \sqrt{49 + 25}

<em>d = </em>\sqrt{74} or 8.60

7 0
2 years ago
For each graph, write the equation of the given translation
jasenka [17]

Answer:

Step-by-step explanation:

if you modify the parent function to go <u>up and down</u>

for example parent function is y=|x| to go <u>down</u> 3 you do y=|x|-3

if you modify the parent function to go <u>left  and right</u>

for example parent function is y=|x| to go <u>right </u>3 you do y=|x-3|

a.goes down 3, and 2 to the right

y=|x-2|-3

b. 3 down and 1 to the left

y=(x+1)²-3

c. 5 up and 2 to the right

d. 1 up and 5 to the right

6 0
3 years ago
Sharon is 18 and would like to buy a house when she is 34. What is the discount factor for today's prices if the housing values
nlexa [21]
If I did the math right it should be A. 12.0%
6 0
2 years ago
Read 2 more answers
How do you graph y=-3x+4
Art [367]

It's a linear function. The graph is a straight line, therefore we need only two points.

Select any value of x and calculate the value of y:

y = -3x + 4

for x = 0 → y = -3(0) + 4 = 4 → (0, 4)

for x = 2 → y = -3(2) + 4 = -2 → (2, -2)

4 0
2 years ago
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

4x=3x

\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

4 0
3 years ago
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