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andre [41]
3 years ago
6

Urgent - Calculus - Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does

not exist, enter DNE.)
f(x) = x^2 − x − 4 on [0, 4]
Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

16

Step-by-step explanation:

You might be interested in
Weights of cars passing over a bridge part 2<br>​
DaniilM [7]

Step-by-step explanation:

The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.

Given:

mean,  mu = 3550 lbs (hope I read the first five correctly, and it's not a six)

standard deviation, sigma = 870 lbs

weights are normally distributed, and assume large samples.

Probability to be estimated between W1=2800 and W2=4500 lbs.

Solution:

We calculate Z-scores for each of the limits in order to estimate probabilities from tables.

For W1 (lower limit),

Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069

From tables, P(Z<Z1) = 0.194325

For W2 (upper limit):

Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954

From tables, P(Z<Z2) = 0.862573

Therefore probability that weight is between W1 and W2 is

P( W1 < W < W2 )

= P(Z1 < Z < Z2)

= P(Z<Z2) - P(Z<Z1)

= 0.862573 - 0.194325

= 0.668248

= 0.67 (to the hundredth)

6 0
3 years ago
Which models show the problem 4
exis [7]

Answer:

the second and last sentences.

Step-by-step explanation:

Its the most reasonable!

7 0
3 years ago
Read 2 more answers
Find the least common denominator for these two rational expressions 7/n^2 -8/7n
lianna [129]

Answer:

7n²

Step-by-step explanation:

7/n² - 8/7n

Least common multiple will be the least common denominator

L.C.M = 7n²

Dividing the L.C.M by denominators and multiplying with numerators;

((7×7) - (n×8))/7n²

= (49 - 8n)/7n²

7n² is the least common denominator

8 0
3 years ago
US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter
Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

           Standard deviation = 112

           Mean = 505

           Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

H_0:\mu \geq 477\\H_a:\mu < 477

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

z=\frac{505-477}{\frac{112}{\sqrt{64}}}

z=2

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0
3 years ago
Trevor is swimming laps to raise money for the local food bank. He earns $1.85 per lap and has already swum 23 laps.
finlep [7]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

The inequality is 1.85x - 42.55 > 100. 42.55 is the amount already raised, 1.85x is number of laps times the money raised by them. 
5 0
3 years ago
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