Answer:
Any rational root of f(x) is a factor of 9 divided by a factor of 12.
Step-by-step explanation:
Given:
f(x) = 12x³– 5x² + 6x + 9
Required; Rational root of f(x)
The rational root theorem states that: each rational solution
x = p⁄q, written in lowest terms so that p and q are relatively prime
Where
p = factors of the constant
q = factors of the lead coefficient.
Given that
f(x) = 12x³– 5x² + 6x + 9
The constant is 9
And the lead coefficient is 12
The factor of these two are
9; ±1 , ±3, ±9
12: ±1, ±2, ±3, ±4, ±6, ±12
Then the rational root of f(x) is
factor of 9 divided by a factor of 12.
Possible Rational Roots
= (±1 , ±3, ±9) / (±1, ±2, ±3, ±4, ±6, ±12)
The correct statement according to the rational root theorem is
The rational root of f(x) is
factor of 9 divided by a factor of 12
