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Ratling [72]
3 years ago
15

Find the common ratio for the geometric sequence for which a1=3 and a5=48

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0

Answer:

The common ratio for the geometric sequence is:

2

Step-by-step explanation:

In general, the terms of geometric sequence is given as:

a,ar,ar^2,ar^3,...

where a is the first term and r is the common ratio

Here, a=3

and fifth term of geometric sequence=48

i.e. ar^4=48

3r^4=48\\\\r^4=16\\\\r^4=2^4\\\\r=2

Hence, the common ratio for the geometric sequence is:

2

Rama09 [41]3 years ago
7 0

The ratio is common, so you could write:

a1 * r^4 = a^5 (you do r^4 because there are 4 times you need to multiply by the ratio to get from a1 to a5)

Plug in the values:

3 * r^4 = 48

Divide by 3:

r^4 = 16

Take the fourth root of both sides:

r = 2

The common ratio is 2.

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Here you have a system of 2 equations and 2 unknowns. An easy way to solve this type is to isolate one of the variables.

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b =
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3 years ago
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masya89 [10]

Remark

You are dealing with a right angle triangle. You can use one of Sin(x) Cos(x) or Tan(x). Since the Hypotenuse is involved and since you are given the adjacent side, Cos(71) is what you will need.

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{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

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