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Cerrena [4.2K]
2 years ago
8

BRAINY WILL BE AWARDED

Mathematics
2 answers:
Tanya [424]2 years ago
7 0

Answer:

Yes he will be able to buy 2

Step-by-step explanation:

Half of $8.90 is $4.45

$8.90 + $4.45 = $13.35

Studentka2010 [4]2 years ago
6 0

Answer:

The answer to oyur question is: yes.

Step-by-step explanation:

Data

Craig has  £13.40

Courses = £8.90

2nd half price

Process

Get how much cost the second one

                                                              8.90/ 2 = £ 4.45

Total cost = 8.90 + 4.45

                = £ 13.35

Craig has £13.40, yes, he can affort to buy a second meal.

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Angles C and E are supplementary. The M>C = 112 and M>E = (3x + 50) Solve for X.
maxonik [38]

Answer:

The value of x is 6

Step-by-step explanation:

we know that

If two angles are supplementary, then their sum is equal to 180 degrees

so

In this problem

m∠C+m∠E=180°

we have

m∠C=112°

m∠E=(3x+50)°

substitute and solve for x

112°+(3x+50)°=180°

3x+162=180

3x=180-162

3x=18

x=6

7 0
3 years ago
If y=-8 when x=2, find y when x=3
tatuchka [14]

I don't really know if the question is complete but...

y = x -10    can be a solution

so y would be -7 when x is 3

7 0
3 years ago
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kicyunya [14]

Answer:

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5 0
2 years ago
Read 2 more answers
Suppose that 40 deer are introduced in a protected wilderness area. The population of the herd
Scorpion4ik [409]

The horizontal asymptote of the function is the minimum number of deer in the area.

  • The equation of horizontal asymptote is: \mathbf{y = 40}
  • The horizontal asymptote means that, the number of deer will never be less than 40

The equation is given as:

\mathbf{f(x) = \frac{40 + 2x}{1 + 0.05x}}

Expand the numerator

\mathbf{f(x) = \frac{40(1 + 0.05x)}{1 + 0.05x}}

Cancel out the common factor

\mathbf{f(x) = 40}

Hence, the equation of horizontal asymptote is:

\mathbf{y = 40}

The horizontal asymptote means that, the number of deer will never be less than 40

Read more about horizontal asymptotes at:

brainly.com/question/4084552

8 0
2 years ago
Someone help please?
alukav5142 [94]

Answer:

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3 0
2 years ago
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