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4 years ago

Can you please help me with this l will give you Brainliest.

Mathematics

2 answers:

nydimaria [60]3 years ago

6 0

The value of a number increases when its subtracted by a negative. In the expression 5 - -4, since 4 is a negative integer that’s being subtracted, it’s added to the 5 — which would equal 9.

VARVARA [1.3K]4 years ago

3 0

Answer:

Step-by-step explanation:

Hello

When you have two negative symbols, you have to multiplied them, so:

-*-= +

+*+= +

+*-=-

-*+ = -

You can to do more research lookin this: "Algebraic operations with symbols" or "The sign´s law"

I attached a illustrative image about this.

Then,

5 - (-4) (here is with -*- )

5 + 4

Best regards

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2007 Federal Income Tax Table Single: Over But not over The tax is $0 $7,825 10% of the amount over $0 $7,825 $31,850 $788 + 15%

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Step-by-step explanation:

3 0

2 years ago

Solve: 3x - 2x + 4 = 5x - 4x - 8 A)3 B)6 C)-3 D)no solution

tensa zangetsu [6.8K]

3x - 2x + 4 = 5x - 4x - 8

First, let's focus on the left side of the problem (3x - 2x + 4). Let's subtract 3x - 2x which will get us 1, and since a variable by itself is considered 1, we can just put the variable.
$1 + 4 = 5x - 4x - 8$

Second, now let's focus on the right side of the problem (5x - 4x - 8). Subtract 5x - 4x to once again get 1. Replace it with the variable and leave the rest.
$x = 4 = x - 8$

Third, we can now cancel out x on each side. This will leave us with 4 = -8, which is false, meaning that there is no solution to this problem.

$\fbox {D) No Solution}$

4 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form for the line that passes through (5,0) and is perpendicular to the line described by y

natta225 [31]

For this case we have to;

We have that an equation in slope-intercept form is given by:

$y = mx + b$

Where:

m is the slope

b is the cut point with the y axis

Also, by definition, two lines are perpendicular when the product of their slopes is -1. That is: $m_ {1} * m_ {2} = - 1$

We have the line as data: $y_ {1} = \frac {-5} {2} x + 6$

Then $m_ {1} = \frac {-5} {2}$

We found $m_ {2}$ :

$m_ {1} * m_ {2} = - 1$

$\frac {-5} {2} * m_ {2} = - 1$

$m_ {2} = \frac {-1} {(\frac {-5} {2})}$

$m_ {2} = \frac {(2) (- 1)} {(- 5) (1)}$

$m_ {2} = \frac {2} {5}$

Thus, $y_ {2} = \frac {2} {5} x_ {2} + b_ {2}$

We must find $b_ {2}$ :

We know that $y_ {2}$ passes through the point $(x_ {2}, y_ {2}) = (5,0)$

We substitute the point in the equation of $y_ {2}$ :

$0 = \frac {2} {5} (5) + b_ {2}\\0 = 2 + b_ {2}\\b_ {2} = - 2$

Thus, $y_ {2} = \frac {2} {5} x_ {2} -2$

Then the equation in slope-intercept for the line that passes through (5,0) and is perpendicular to the line described by $y_ {1} = \frac {-5} {2} x_{1} + 6$ is: $y_ {2} = \frac {2} {5} x_ {2} -2$