Answer:
4
Step-by-step explanation:
Each bar represents a range in area. The first bar represents the number of houses with an area of more than 50 but less than 100. It's height is 4, so there are 4 of those houses.
Answer:
Part a) Rectangle
Part b) Triangle
Step-by-step explanation:
Part A) A cross section of the rectangular pyramid is cut with a plane parallel to the base. What is the name of the shape created by the cross section?
we know that
When a geometric plane slices any right pyramid so that the cut is parallel to the plane of the base, the cross section will have the same shape (but not the same size) as the base, So, in the case of a right rectangular pyramid, the cross section is a rectangle
Part b) If a cross section of the rectangular pyramid is cut perpendicular to the base, passing through the top vertex, what would be the shape of the resulting cross section?
we know that
Cross sections perpendicular to the base and through the vertex will be triangles
false false false false false
The anwer plus working is 6668/4=151.55
Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]:

Derivative Property [Addition/Subtraction]:

Derivative Rule [Basic Power Rule]:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Integration
Integration Rule [Reverse Power Rule]:

Integration Property [Multiplied Constant]:

Integration Methods: U-Substitution and U-Solve
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify given.</em>
<em />
<u>Step 2: Integrate Pt. 1</u>
<em>Identify variables for u-substitution/u-solve</em>.
- Set <em>u</em>:

- [<em>u</em>] Differentiate [Derivative Rules and Properties]:

- [<em>du</em>] Rewrite [U-Solve]:

<u>Step 3: Integrate Pt. 2</u>
- [Integral] Apply U-Solve:

- [Integrand] Simplify:

- [Integral] Rewrite [Integration Property - Multiplied Constant]:

- [Integral] Apply Integration Rule [Reverse Power Rule]:

- [<em>u</em>] Back-substitute:

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.
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Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration