Answer:
Step-by-step explanation:
Given the simultaneous equation
3x+4y=15. Equation 1
3x-y=30. Equation 2
Using elimination method
Sutract equation 2 from 1
Then, will have
3x-3x+4y--y=15-50. -×-=+
4y+y=-15
5y=-15
Divide Both sides by 5
y=-15/5
y=-3
From equation 2
3x-y=30
3x--3=30
3x+3=30
3x=30-3
3x=27
Divide both side by 3
x=27/3
x=9
Then, x=9 and y=-3
The teacher would have to grade 322 problems
14 (problems) x 23 (students)
Answer: 322
Answer:
384 cm²
Step-by-step explanation:
The shape of the figure given in the question above is simply a combined shape of parallelogram and rectangle.
To obtain the area of the figure, we shall determine the area of the parallelogram and rectangle. This can be obtained as follow:
For parallelogram:
Height (H) = 7.5 cm
Base (B) = 24 cm
Area of parallelogram (A₁) =?
A₁ = B × H
A₁ = 24 × 7.5
A₁ = 180 cm²
For rectangle:
Length (L) = 24 cm
Width (W) = 8.5 cm
Area of rectangle (A₂) =?
A₂ = L × W
A₂ = 24 × 8.5
A₂ = 204 cm²
Finally, we shall determine the area of the shape.
Area of parallelogram (A₁) = 180 cm²
Area of rectangle (A₂) = 204 cm²
Area of figure (A)
A = A₁ + A₂
A = 180 + 204
A = 384 cm²
Therefore, the area of the figure is 384 cm²