Answer:
please see photo for details
Step-by-step explanation:
1/a + 1/b + 1/c = 1/(a+b+c)
=> 1/a + 1/b = 1/(a+b+c) -1/c
=> (b+a)/ab = {c - (a+b+c)/c(a+b+c)
=> (a+b)/ab = -(a+b)/(ac+bc+c^2)
=> 1/ab = -1/(ac+bc+c^2)
=> -ab = ac+bc+c^2
=-c^2 = ab+bc+ca
Similarly we can show that
-b^2 =ab+bc+ca and -c^2 = ab+bc+ca
So a=b=c. since -a^2 = -b^2 = - c^2
Then 1/a + 1/b + 1/c = 1/(a+b+c) => 3/a= 1/3a
=> 1/a^5 + 1/b^5 + 1/c^5 =3/a^5=(( 3/a )(1/a^4)
= 1/3a × 1/a^4 = 1/3a^5 = 1/(a^5 +b^5+c^^5)
Hope it help
Answer:
Left to right: Zoe, Johana, Kami, Craig
Step-by-step explanation:
The values of x can be found by solving each of the equations.
A) x/-12 -2 = -22 ⇒ x = -12(-22 +2) = 240 . . . (first step: add 2)
B) 3x -21 = 15 ⇒ x = (15 +21)/3 = 12
C) -12x +2 = -22 ⇒ x = (-22 -2)/-12 = 2 . . . (first step: subtract 2)
D) 1/2x +66 = 126 ⇒ x = 2(126 -66) = 120
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Zoe's equation requires adding 2 as the first step. It is equation A.
Craig's equation's solution is half that of Zoe's. 240/2 = 120. Craig's is equation D.
Kami's equation requires subtracting 2 as the first step. It is equation C.
Johana's equation's solution is 6 times that of Kami's. 6·2 = 12. Johana's is equation B.
The names that go in the blanks, left-to-right, are ...
Zoe, Johana, Kami, Craig
