Given: NQ = NT , QS Bisect NT(∴ NS=ST ) , TV Bisects QN (∴ NV=VQ )
To Prove: QS=TV
Proof: In ΔNQT
NQ=NT
∴ VQ=ST
In a isosceles triangle, If two sides are equal then their opposites angles are equal.
∴ ∠NQT=∠NTQ ( ∵ NQ=NT)
In ΔQST and TVQ
ST=VQ (sides of isosceles triangle)
∠NQT=∠NTQ (Prove above)
QT=TQ (Common)
So, ΔQST ≅ TVQ by SAS congruence property
∴ QS=TV (CPCT)
CPCT: Congruent part of congruence triangles.
Hence Proved
Answer:
17%, 1/4, 1.7
Step-by-step explanation:
Convert each to decimals: 17% = .17, 1/4 = .25, then order from least to greatest
Step (1) is incorrect. To divide by a number means to multiply by the reciprocal. In step (1) they did not convert the polynomial into its reciprocal.
Answer:
394.8
Step-by-step explanation:
the missing angle is 180 - 26 - 27 = 127
32/sin 27 = x/sin 26, x(side UV) = 30.899053
Area = 1/2ab sin C
1/2 (30.9)(32) sin 127 = 394.8
