Answer:
The correct option is;
c. Because the p-value of 0.1609 is greater than the significance level of 0.05, we fail to reject the null hypothesis. We conclude the data provide convincing evidence that the mean amount of juice in all the bottles filled that day does not differ from the target value of 275 milliliters.
Step-by-step explanation:
Here we have the values
μ = 275 mL
275.4
276.8
273.9
275
275.8
275.9
276.1
Sum = 1928.9
Mean (Average), = 275.5571429
Standard deviation, s = 0.921696159
We put the null hypothesis as H₀: μ₁ = μ₂
Therefore, the alternative becomes Hₐ: μ₁ ≠ μ₂
The t-test formula is as follows;
Plugging in the values, we have,
Test statistic = 1.599292
at 7 - 1 degrees of freedom and α = 0.05 = ±2.446912
Our p-value from the the test statistic = 0.1608723≈ 0.1609
Therefore since the p-value = 0.1609 > α = 0.05, we fail to reject our null hypothesis, hence the evidence suggests that the mean does not differ from 275 mL.
8n-(2n-3)=12
8n-2n+3=12
6n=12-3
6n=9
n=9/6=3/2
Answer:
An Algebraic Expression that models the situation is 
Step-by-step explanation:
Beginning balance of Jennifer=$4750
Now she deposits a paycheck = p
So, New balance = 4750+p
Now she writes a check = c
Remaining balance = 4750+p-c
Now she writes a check = d
Remaining balance = 4750+p-c-d
Now refunded some money (r) for returning a pair of shoes she bought.
New balance = 4750+p-c-d+r
Hence an Algebraic Expression that models the situation is
There are 26 letters of the alphabet
you want 6-character passwords without repetitionthe first time you pick a letter, you pick from 26 lettersthe second time you pick a letter, you pick from 25 letters (no repetitions !)the third time you pick a letter, you pick from 24 letters, and so onthe answer is 26*25*24*23*22*21=165,765,600 passwords
A.0.8 < 5/6 < 12/13
because 5/6 = .83 and 12/13 = .92
