3 years ago

Does a graph represents a function why or why not

Mathematics

1 answer:

vekshin13 years ago

6 0

It does if the x values don't repeat it they repeat it doesn't

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Shazia sells 25x^2+5x+5 flowers in one day. If she sells the same number of flowers each day for rs 5x each , how much money wil

Mumz [18]

Answer:

$Total = 625x^3 + 125x^2 + 125x$

Step-by-step explanation:

Given

$Flowers = 25x^2 + 5x + 5$

$Unit\ price = 5x$

Required

The total price for 5 days

First, calculate the total for a day.

$1\ day = Unit\ price * Flowers$

$1\ day = 5x * (25x^2 + 5x + 5)$

Open bracket

$1\ day = 125x^3 + 25x^2 + 25x$

For 5 days, the total will be.

Total = days * sales of a day

So, we have:

$Total = 5 * [ 125x^3 + 25x^2 + 25x]$

$Total = 625x^3 + 125x^2 + 125x$

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3 years ago

Alex has 7 pounds of birdseed and 5 bird feeders.

hram777 [196]

Well, we dont know because we cant see the barmodels

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2 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

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3 years ago

A prism is completely filled with 3996 cubes that have edge lengths of 13 in. What is the volume of the prism? Enter your answ

ANEK [815]

First, solve for the volume of each cube through the equation,
V = e³
Substituting the known value,
V = (13 in)³ = 2197 in³
Then, multiply this volume by the number of cubes. Thus, the total volume of the prism,
V = (2197 in³)(3996)
V = 8,779,212 in³

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Suppose you begin with a pile of n stones and split this pile into n piles of one stone each by successively splitting a pile of

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Start with five stones

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