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Travka [436]
3 years ago
9

What does the y-intercept mean in terms of the graph? Select all that apply.

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0
Hello there!

Your answer would have to be C. where the function crosses the y-axis

Hope This Helps!
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If the parent function is \root(3)(x), describe the translation of the function y=\root(3)(x+4)-3
xeze [42]

The parent function moves 4 units right and 3 units down. This is a translation by the vector.

According to the question,

Transformation \sqrt[3]{x} maps  onto \sqrt[3]{x+4} -3 . Take f(x) =  \sqrt[3]{x} and f(x+4)=\sqrt[3]{x+4}.

f(x) =  \sqrt[3]{x}

f(x+4)=\sqrt[3]{x+4}

f(x+4) - 3=\sqrt[3]{x+4} - 3

Analyze the function to see the translations. f(x-4) corresponds to a horizontal translation 4 units in the positive 'x' direction. f(x)-3 corresponds to a vertical translation 3 units in the negative 'y' direction.

Hence, the parent function moves 4 units right and 3 units down. This is a translation by the vector.

Learn more about parent function here

brainly.com/question/7154028

#SPJ4

7 0
2 years ago
What is the pythagorean therum
Nimfa-mama [501]
The Pythagorean theorem is a^2 + b^2 = c^2. You use it when solving for the sides of a triangle.
3 0
3 years ago
Read 2 more answers
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
Mrs. Smith bought 4 dozen doughnuts and paid a total of $13.92. What was the cost of 1 doughout
polet [3.4K]

Answer:

A $0.29

Step-by-step explanation:

4 dozen donuts is 48 donuts. (A dozen is 12 so 4 times 12 is 48). $13.92 divided by 48 is $0.29.

5 0
3 years ago
Read 2 more answers
HOW AM I SUPPOSED TO DO THIS IF YOU DONT KNOW HOW TO DO THIS DONT HELP AN GET ME SOMEONE THAT WILL someone help me
Romashka-Z-Leto [24]
Just take each number in the first table and divide it by the total then x by 100

Eg the first one 24/120 x 100 = 20%
6 0
2 years ago
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