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3 years ago

9

What does the y-intercept mean in terms of the graph? Select all that apply.

1 answer:

mote1985 [20]3 years ago

7 0

Hello there!

Your answer would have to be C. where the function crosses the y-axis

Hope This Helps!

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Pleeeeeeassesesesaerxvdrcgcdrcxf help me

Aleksandr-060686 [28]

Answer:

The solution is r <u>></u> 7.

Closed circle at 7 with an arrow pointing to the right

Step-by-step explanation:

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3 years ago

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Stanley has a collection of seashells. He found 35% of his collection on Florida beaches. If Stanley has 49 seashells from Flori

m_a_m_a [10]

Answer:

The number of seashells he have in his collection all together is <u>140</u>.

Step-by-step explanation:

Given:

Stanley has a collection of seashells. He found 35% of his collection on Florida beaches.

Stanley has 49 seashells from Florida.

Now, to find the number of seashells of his collection altogether.

Let the number of seashells all together be $x.$

Percentage of seashells found on Florida beaches = 35%.

Number of seashells found on Florida beaches = 49.

Now, to get the number of seashells altogether we put an equation:

$35\%\ of\ x=49.$

⇒ $\frac{35}{100} \times x=49$

⇒ $0.35\times x=49$

⇒ $0.35x=49$

Dividing both sides by 0.35 we get:

⇒ $x=140.$

Therefore, the number of seashells he have in his collection all together is 140.

4 0

3 years ago

What is the scale factor of a model car if the scale is 1 inch=2 feeet

crimeas [40]

1 foot = 12 inches
1in : 2 feet
1in : 24in

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3 years ago

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Hey mate answer te question please

andrezito [222]

Answer:

7 $\frac{37}{55}$

Step-by-step explanation:

In order to solve an equation like this, you'll need to find a common denominator for your Fraction.

7 $\frac{2}{5}$ + $\frac{3}{11}$

7 $\frac{22}{55}$ + $\frac{15}{55}$

7 $\frac{37}{55}$

4 0

3 years ago

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .

The number of fish tripled in the first year. This means that $P(1) = 3P(0) = 3(80) = 240$ .

Using the equation for P(1), that is, P(t) when $t = 1$ , we find the value of r.

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

$240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}$

$280*(2000 + 80(e^{r} - 1)) = 160000e^{r}$

$280*(2000 + 80e^{r} - 80) = 160000e^{r}$

$280*(1920 + 80e^{r}) = 160000e^{r}$

$537600 + 22400e^{r} = 160000e^{r}$

$137600e^{r} = 537600$

$e^{r} = \frac{537600}{137600}$

$e^{r} = 3.91$

Applying ln to both sides.

$\ln{e^{r}} = \ln{3.91}$

$r = 1.36$

This means that the expression for the size of the population after t years is:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

4 0

3 years ago