Answer:
See the answer below
Explanation:
Free hanging ear lobe's allele = E
Attached ear lobe's allele = e
E is dominant over e.
- <em>A heterozygous person with Ee genotype will produce </em><em>E</em><em> and </em><em>e </em><em>egg/sperm during gametogenesis.</em>
<em> E gamete = </em><em>50%</em>
<em>e gamete = </em><em>50%</em>
2. A man and a woman both heterozygous for earlobe
Ee x Ee
<em> Offspring = </em><em>EE, 2Ee, ee</em>
<em>Probability of a child having free ear lobe = </em><em>3/4</em>
<em> Probability of a child having attached earlobe = </em><em>1/4</em>
3. A man attached ear lobe with a woman with free earlobe produced three children out of which two have free earlobes and one has attached ear lobes.
<em>Genotype of man with attached earlobe = </em><em>ee</em>
<em> Genotype of woman with free earlobes = </em><em>Ee</em><em> (since they produced both free and attached earlobe children)</em>
ee x Ee
<em>Genotype of children = </em><em>Ee, ee, Ee </em><em>and</em><em> ee</em>
Ee = free earlobes
ee = attached earlobe