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ikadub [295]
3 years ago
15

At what x-values do the graphs of the functions y=cos 2x and y = cos^2 x-1 intersect over the interval 0 ≤ x ≤ pi. There must be

two selections there are two anwsers!

Mathematics
2 answers:
salantis [7]3 years ago
6 0

Answer:

x=pi/2 and x=3pi/2

Step-by-step explanation:

baherus [9]3 years ago
4 0

Answer:

x=\frac{\pi}{2}  and  x=\frac{3\pi}{2}

Step-by-step explanation:

We need to solve the 2 equations to figure out the x-values (intersecting points).

<em>Note: </em>The identity  cos^{2}x=\frac{1}{2}+\frac{1}{2}cos(2x)

cos(2x)=cos^{2}(x)-1\\cos(2x)=(\frac{1}{2}+\frac{1}{2}cos(2x))-1\\cos(2x)=\frac{1}{2}cos(2x)-\frac{1}{2}\\\frac{1}{2}cos(2x)=-\frac{1}{2}\\cos(2x)=-1\\2x=cos^{-1}(-1)\\2x=\pi, 3\pi\\x=\frac{\pi}{2}, \frac{3\pi}{2}

So they intersect at  x=\frac{\pi}{2}, \frac{3\pi}{2}

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<h3>How to graph the inequalities?</h3>

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