Answer:
(- 1, - 1 )
Step-by-step explanation:
Given the 2 equations
x = 4y + 3 → (1)
2x + y = - 3 → (2)
Substitute x = 4y + 3 into (2)
2(4y + 3) + y = - 3 ← distribute parenthesis and simplify left side
8y + 6 + y = - 3
9y + 6 = - 3 ( subtract 6 from both sides )
9y = - 9 ( divide both sides by 9 )
y = - 1
Substitute y = - 1 into (1) for corresponding value of x
x = 4(- 1) + 3 = - 4 + 3 = - 1
solution is (- 1, - 1 )
Remove parentheses
-2x + 12 - 9 = 2 + 9 + 2x
Simplify -2x + 12 -9 to -2x + 3
-2x + 3 = 2 + 9 + 2x
Simplify 2 + 9 + 2x to 2x + 11
-2x + 3 = 2x + 11
Add 2x to both sides
3 = 2x + 11 + 2x
Simplify 2x + 11 +2x to 4x + 11
3 = 4x + 11
Subtract 11 from both sides
3 - 11 = 4x
Simplify 3 - 11 to - 8
-8 = 4x
Divide both sides by 4
-8/4 = x
Simplify 8/4 to 2
-2 = x
Switch sides
x = -2
Answer:
(Choice A)
Juanita gets a strike next game.'
Step-by-step explanation:
Your question is obviously incomplete.
Complete question is:
Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina getting a strike next game is 0.17. Which of these events is more likely?
(Choice A)
Juanita gets a strike next game.'
(Choice B)
Nina gets a strike next game.
(Choice C)
Neither. Both events are equally likely.
Answer:
Probability of Juanita : P(J)= 24% => 0.24
probability of Nina getting a strike next game: P(N) = 0.17
As you can see 0.24 > 0.17 ----> P(J)>P(N)
Thus it can be concluded that Juanita gets a strike next game is more likely.
so, choice A
Answer:
they are both straight
Step-by-step explanation:
Answer: 0.6767
Step-by-step explanation:
Given : Mean =
errors per page
Let X be the number of errors in a particular page.
The formula to calculate the Poisson distribution is given by :_
Now, the probability that a randomly selected page does not need to be retyped is given by :-
Hence, the required probability :- 0.6767
