The value of
is 31
Explanation:
The given expression is 
We need to determine the value of 
The value of
can be determined by substituting
in the expression 
Thus, we have,

Adding the terms, we have,

Thus, the value is 31.
Therefore, the simplified value of the expression by substituting
in the expression
is 31.
The answer is d because 3x5=15
The price is now 13.92 (13.9236) <span>16.98-13.92 </span>It's a $3.06 discount
Answer:
2 is 12 3 is 3 faces 4 is 151 that's all i can tell u at least i helped
Step-by-step explanation:
Function assign value from one set to another. The value of f(5), if f(1) = 3.2 and f(x+1) = Five-halves(f(x)) is 125.
<h3>What is Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
As it is given the value of the function f(1) is 3.2, while the value of f(x+1) is
, therefore, in order to find the value of f(5), we need to calculate the value of f(4).
f(2)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(2)=f(1+1) = \dfrac{5}{2}[f(1)]\\\\f(2) = 2.5 \times 3.2\\\\f(2) = 8](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%282%29%3Df%281%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%281%29%5D%5C%5C%5C%5Cf%282%29%20%3D%202.5%20%5Ctimes%203.2%5C%5C%5C%5Cf%282%29%20%3D%208)
f(3)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(3)=f(2+1) = \dfrac{5}{2}[f(2)]\\\\f(3) = 2.5 \times 8\\\\f(3) = 20](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%283%29%3Df%282%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%282%29%5D%5C%5C%5C%5Cf%283%29%20%3D%202.5%20%5Ctimes%208%5C%5C%5C%5Cf%283%29%20%3D%2020)
f(4)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(4)=f(3+1) = \dfrac{5}{2}[f(3)]\\\\f(4) = 2.5 \times 20\\\\f(4) = 50](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%284%29%3Df%283%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%283%29%5D%5C%5C%5C%5Cf%284%29%20%3D%202.5%20%5Ctimes%2020%5C%5C%5C%5Cf%284%29%20%3D%2050)
f(5)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(5)=f(4+1) = \dfrac{5}{2}[f(4)]\\\\f(5) = 2.5 \times 50\\\\f(5) = 125](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%285%29%3Df%284%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%284%29%5D%5C%5C%5C%5Cf%285%29%20%3D%202.5%20%5Ctimes%2050%5C%5C%5C%5Cf%285%29%20%3D%20125)
Hence, the value of f(5), if f(1) = 3. 2 and f(x+1) = Five-halves(f(x)) is 125.
Learn more about Function:
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