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3 years ago

!MATH EMERGENCY PLEASE ANSWER CORRECTLY

Mathematics

1 answer:

hram777 [196]3 years ago

6 0

Answer:

It is the last one.

Step-by-step explanation:

With a problem like this you must rank highest to lowest and add anything that has the same look. Take 2squared and 5 squared for example, They both are squared so you can add them. Hope this Helped.

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Will give brailiest to first

Komok [63]

Answer:

$f(x)=x^(2)-2x+3$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Evaluate and reduce: 12 + (12) Enter the number that belongs in the green box. [?]

Firlakuza [10]

Answer:

Step-by-step explanation:

12 + (12)

first do for the bracket

12 + 12

3 0

3 years ago

Which pairs of points would result in a line with a rate of change of 2:1? select all that apply

Reil [10]

Answer:

A,C,D

Step-by-step explanation:

Complete Question:

"Which pairs of points would result in a line with a rate of change of 2:1? select all that apply"

A.(−4,−11) and (−2−7)

B.(5,6) and (−5, 12)

C.(0,−3)and (−4,−11)

D. (0,−3) and (5, 7)

Rate of change is the slope. 2:1 would mean a slope of simply, 2.

We need to find slope of each of the choices from A - D and see which one has 2. The formula would be:

$m=\frac{y_2-y_1}{x_2-x_1}$

Where m is the slope and

x_1 is first x point

x_2 is second x point

y_1 is first y point

y_2 is second y point

Let's calculate slope of each of the choices.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-7+11}{-2+4}\\m=2$

THis one is okay.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{12-6}{-5-5}\\m=-\frac{3}{5}$

THis one is not 2:1.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-11+3}{-4-0}\\m=2$

THis one is okay.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{7+3}{5-0}\\m=2$

This one is okay.

Hence, A, C, and D all have rate of change of 2:1

4 0

3 years ago

Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?

worty [1.4K]

Answer:

Step-by-step explanation:

$(x+y+z)(xy+xz+yz)=18$ Equation 1

$x^2(y+z)+y^2(x+z)+z^2(x+y)=6$ Equation 2

What is the value of $xyz$ where each variable represents a real number?

Let's expand equation 1:

$(x+y+z)(xy+xz+yz)=18$

$x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18$

Simplify each term if can:

$x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18$

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have $x^2$ and if I factored $x^2$ from first two terms I would have $x^2(y+z)$ which is the first term of left hand side of equation 2.