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meriva
4 years ago
7

Which of the following elements has properties different than the rest? H K N O

Chemistry
2 answers:
Helga [31]4 years ago
7 0
<h3>Whichof the following elements has properties different than the rest ?</h3><h3>B. K</h3><h3>Hope I helped, sorry if not tho</h3>
lana66690 [7]4 years ago
3 0
İ think K because K is solid bur others are gas
good luck
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Melting gold with other metals makes 10-karat gold. Which term best describes 10-karat gold?
34kurt

Gold is known to be an element. The term that best describes 10-karat gold is that it is an homogeneous mixture.

  • Gold as an element of often has an ideal state of purity where there contains nothing but gold atoms.

A heterogeneous mixture is known to be a mixture that cannot be chemically sound everytime. Gold jewelry is known to be a homogeneous mixture as it is always will look good and remain unchanged for a long time.

As good example of homogeneous products, e.g  a 1-kilogram 24-karat gold bar has unique properties.

Learn more about Gold from

brainly.com/question/11083304

5 0
3 years ago
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A malfunction at a power station causes a power surge in certain homes near the station. Some televisions and computers begin ma
Elina [12.6K]

Answer:A surege protector

Explanation:right thx

4 0
3 years ago
Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.
Lelechka [254]

Explanation:

(a). The given data is as follows.

Volume of one glass of water = 2.2 \times 10^{2} ml = 220 ml

Volume of 4 glass of water = 220 \times 4 = 880 ml

We known that density of water is 1 g/ml.  Therefore, calculate the mass of water as follows.

       Mass of water = 880 ml \times 1 g/ml

                               = 880 gm

                               = 0.88 Kg               (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

            Q = mC \Delta T

\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C

Putting the given values into the above formula as follows.

         Q = mC \Delta T

             = 0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C

             = 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b).      As we know that the heat of fusion of ice is 333 J/g.

So, energy required for 8.4 \times 10^{2} g or 840 g is as follows.

          333 \times 840 = 279.72 kJ

Heat capacity of water= 4.184 J/g^{o}C

Now, heat energy will be as follows.

           Q = 4.184 \times 840 g \times 37^{o}C

               = 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

                                                  = 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ  of heat.

6 0
4 years ago
Which numbers should go in the blanks when this equation is balanced? _Pb(NO3)2 +_NaCl-&gt;NaNO3+_PbCl2
ASHA 777 [7]

Answer: First, you need a blank in front of NaCl or else you cannot balance this equation.  However, if you do put a blank there:

1, 2, 2, 2

Explanation:

Here is the balanced equation

1 Pb(NO3)2 + 2 NaCl-> 2 NaNO3+ 1 PbCl2

8 0
3 years ago
Which of the following explains this observation?
NikAS [45]
It would be C i’m pretty sure
6 0
3 years ago
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