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saul85 [17]
3 years ago
13

Which of the following explains this observation?

Chemistry
1 answer:
NikAS [45]3 years ago
6 0
It would be C i’m pretty sure
You might be interested in
H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

  • an equilibrium constant is, first of all, a fraction;
  • in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
  • in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
  • each concentration should be raised to the power of the coefficient in the balanced chemical equation;
  • only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

4 0
3 years ago
The mass of Carbon is 12 g/mol and the mass of oxygen is 16 g/mol. What is the approximate percent composition by mass of CO2 (f
nikitadnepr [17]

Answer:

the last one

27% by 73%

Explanation:

12/44*100 for C

and

16/44*100 for O

5 0
3 years ago
What is the volume of 500g of CO2?
Airida [17]

Weighs 0.001836 gram per cubic centimeter or 1.836 kilogram per cubic meter


Try to see if this helps

3 0
3 years ago
Read 2 more answers
I need help with question 17 and 18 and it’s very hard and I’m struggling with it and if you need to see the picture big then cl
lidiya [134]
17 is oxygen and and 18 is its waste
7 0
3 years ago
Please help me with this chemistry problem
Margarita [4]

Answer:

50 g of K₂CO₃ are needed

Explanation:

How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?

We analyse data:

500 g is the mass of the solution we want

10% m/m is a sort of concentration,  in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution

Therefore we can solve this, by a rule of three:

In 100 g of solution we have 10 g of K₂CO₃

In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃

6 0
4 years ago
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