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r-ruslan [8.4K]
4 years ago
11

Short, hairlike appendage

Chemistry
1 answer:
LekaFEV [45]4 years ago
6 0
Cilium part of a cell
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Jose mixed two clear liquids together in a beaker in equal amounts. Jose measured the mass. The mass of the two combined solutio
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Who cares. Joe can solve his own problem instead of making people do it. (This was not toward you. This was supposed to be funny)
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3 years ago
Gold can be separated from sand by panning or by a sluice-box. In panning, water is mixed with the sand and the resulting slurry
ArbitrLikvidat [17]

Answer:

<u><em>Decantation</em></u><em> by means of difference in relative densities.</em>

Explanation:

The specific gravity (relative density) of the gold to the soil/sand is the physical property exploited in panning gold. The particles with lower density would float whilst the heavier gold sinks lower to the bottom of the pan by gravity and is decanted off.

I hope this explanation is easy to comprehend.

6 0
3 years ago
Why is it necessary for the spins of two electrons that occupy one orbital, to be in the opposite directions? What is that law c
Lyrx [107]

Answer:

The Pauli Exclusion Principle

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3 0
3 years ago
If a lab requires each a lab group (3 students) to have 25 ml of a solution and it takes 15 grams of AgNO₃ cuprous nitrate, to m
pochemuha

Answer:

0.375 grams are needed to make 25 mL solution.

Explanation:

Mass of AgNO_3 cuprous nitrate required to make 1 l of solution = 15 g.

1 L = 1000 mL

Mass of AgNO_3 cuprous nitrate required to make 1000 mL of solution = 15 g

Mass of AgNO_3 cuprous nitrate required to make 1 mL of solution:

=\frac{15}{1000} g

Mass of AgNO_3 cuprous nitrate required to make 25 mL of solution:

=\frac{15}{1000} \times 25 g=0.375 g

0.375 grams are needed to make 25 mL solution.

4 0
3 years ago
What is the mass/volume percent of a solution with 75g of Na2CO3 dissolved in 20.0 g of water?
tresset_1 [31]

Answer:

percent by mass = 79%

Explanation:

Data Given:

mass of solute (Na₂CO₃) = 75 g

mass of solvent ( water ) = 20 g

mass percent of solution = ?

Solution:

Formula used to find percent by mass

                          mass of solute / mass of solution x 100 . . . . . . (1)

first we have to find mass of solution

              mass of solution = mass of solute + mass of Solvent . . . . (2)

put values in equation 2

             mass of solution = 75 g + 20 g

             mass of solution = 95 g

Now,

put values in equation 1

 Percent by mass = mass of solute / mass of solution x 100

 Percent by mass = 75 g / 95 g x 100

 Percent by mass = 79 %

so,

The percent of the solution by mass = 79%

***Note:

The same work can be used for the other values too i.e. if you have 20 g of solute and 75 g solvent.

5 0
3 years ago
Read 2 more answers
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