Answer:

Step-by-step explanation:
Given
--- scale factor
Required [missing from the question]:
The ratio of width of the model to the original
From the question, we understand that the scale factor is: 2 : 15
The ratio of the width of the model to the original equals the given scale factor i.e.

Answer:
- North Middle School = 10 students
- Central Middle School = 6 students
- South Middle School = 4 students
Step-by-step explanation:
First calculate the total number of students in all the schools:
= 618 + 378 + 204
= 1,200 students
Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.
North Middle school:
= 618/1,200 * 20
= 10 students
Central Middle School:
= 378 / 1,200 * 20
= 6 students
South Middle School:
= 204/1,200 * 20
= 4 students
The missing value in the logarithm are as follows:
- log₃ 7 - log₃ 2 = log₃ (7 / 2)
- log₉ 7 + log₉ 4 = log₉ 28
- log₆ 1 / 81 =
- - 4 log₆ 3
<h3>How to solve logarithm?</h3>
Using logarithm rule,
logₐ b - logₐ c = logₐ (b / c)
logₐ b + logₐ c = logₐ (b × c)
Therefore,
log₃ 7 - log₃ 2 = log₃ (7 / 2)
log₉ 7 + log₉ 4 = log₉ (7 × 4) = log₉ 28
log₆ 1 / 81 = log₆ 81⁻¹ = log₆ 3⁻⁴ = - 4 log₆ 3
learn more on logarithm here: brainly.com/question/24515212
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The new mixture exists 56.5% peanuts.
<h3>How to estimate the total number of peanuts required for the mixture?</h3>
The first batch of 9 lb of mixed nuts possesses 40% peanuts.
This means the quantity of peanuts exists:
9
40/100 = 3.6 lb
The second batch of 9 lb of mixed nuts possesses 73% peanuts.
This means the quantity of peanuts exists:
9
73/100 = 6.57 lb
The total quantity of peanuts in the mix exists
3.6 lb + 6.57 lb = 10.17 lb
There exist 9 lb + 9 lb = 18 lb of mix.
Therefore, the percent of peanuts in the mix exists:
10.17 / 18
100 = 56.5%
The new mixture exists 56.5% peanuts.
To learn more about the total quantity refer to:
brainly.com/question/18919760
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