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Kitty [74]
3 years ago
7

(3 2/3 + 17 1/5) - ( 11 3/5 + 2 1/3) =

Mathematics
2 answers:
ELEN [110]3 years ago
6 0
6 14/15 take the common factor of each and solve
Ipatiy [6.2K]3 years ago
4 0

Answer:

6 14/15

Step-by-step explanation:

I would say simplifie the paratensies.

First:

3 2/3+ 17 1/5 =

Common factor of 3 and 5 is 15

3 10/15 + 17 3/15 = 20 13/15

Second:

11 3/5 + 2 1/3 =

Common factor of 3 and 5 is 15

11 9/15 + 2 5/15 = 13 14/15

20 13/15 - 13 14/15 = 7 13/15 - 14/15 = 7 - 1/15 = 6 14/15

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Andrew [12]
D, 2 and 1/4 or 2.25
4 0
3 years ago
Plz help me well mark brainliest if correct!!....
erastovalidia [21]

Answer:

22 in. or B

Step-by-step explanation:

add all the sides

7 0
3 years ago
Read 2 more answers
80 POINTS, I WILL MARK BRAINLYEST, LEGIT JUST 4 QUESTIONS. PLEASE ANSWER WITH WORK OR NO POINTS FOR YOU!!!!
Korolek [52]

Answer:

see below

Step-by-step explanation:

given: size of television is height = 37 in,  length = 71 in.

A.  using Pythagorean theorem:

parts given are legs which is the sides

looking for the hypotenuse.

B.  formula:

a² + b² = c²    or   H² + L² = D²

where H = height = 37

           L = length = 71

           D = diagonal (which is req'd)

C.   D² = 37² + 71²

      D = \sqrt{1369+ 5041}

      D = \sqrt{6410}

     D = 80 in (missing length)

D. size of television:

    37 x 71 in

    Diagonal is 80 in

hope it helps and good luck!

5 0
3 years ago
Parisian sewer #1 contains 9 fewer gigantic rats—rats as big as cats, some might say—than parisian sewer #2. parisian sewer #2 c
Leya [2.2K]

There are different kinds of math problem. There will be 11 rats in sewer #1.

<h3>What are word problem?</h3>

The term  word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.

Lets take

sewer #1 = a

sewer #2 = b

sewer #3 = c

Note that   A=B-9

So then you would have:

A=B-9

B=C- 5

A+B+C=56

Then you have to do a substitution so as to find C:

(B- 9) + (C-5) + C = 56

{ (C- 5)-9} + (C-5) + C = 56

3C - 19 = 56

3C = 75

B = C- 5

B = 25 - 5

Therefore, B = 20

A = B - 9

= 25 - 9

=11

Therefore, there are are 11 rats in sewer #1

Learn more about  Word Problems from

brainly.com/question/21405634

8 0
2 years ago
Monthly water bills for a city have a mean of $108.43 and a standard deviation of $36.98. Find the probability that a randomly s
GaryK [48]

Answer:

The bill size can be considered usual.

Step-by-step explanation:

Mean (μ) = $108.43

Standard deviation (σ) = $36.98

Now, consider the distribution to be normal distribution :

P(Z=\frac{X-\mu}{\sigma}>\frac{a-\mu}{\sigma})=P(Z>\frac{173-108.43}{36.98})\\\\\implies P(Z>1.75)

Now, finding values of z-score from the table. We get,

P(Z > 1.75) = 0.9599

⇒ 95.99%

So, only 4.01 % of the people in the city wastes water.

Hence, the bill size can be considered usual.

6 0
3 years ago
Read 2 more answers
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