The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
x^2 = 9
Step-by-step explanation:
Both 3 and -3 are 9 when squared.
Answer:
<em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em><em>1</em><em> </em>
Step-by-step explanation:
11(1331)
11(121)
11(11)
(1)
10(1000)
10(100)
10(10)
(1)
(11/10*11/10*11/10)^(1/3)
=11/10
=1.1.
Step-by-step explanation:
b2 =5
.....................
