In order to get who was right we need to solve the expression:
2a^2b(-2ab^3)^-2
The above can be written as fraction to get:
(2a^2b)/(-2ab^3)^2
=(2a^2b)/(4a^2b^6)
=1/2(a^(2-2)b^(1-6))
=1/2a^0b^-5
=1/2b^(-5)
This implies that neither of the was right
1) x+y=302x+9y=172x=-y+30-2y+60+9y=1727y=112y=16x=14
14 2-point questions and 16 9-point questions
2) c+a=163
6c+13a=1566
c=-a+163
-6a+976+13a=1566
7a=588
a=84
c=79
84 adult tickets and 79 children tickets
3) a+c=15; ax+cy=132
8+7=15; 8x+7y=132
a+c=9; ax+cy=72
4+5=9; 4x+5y=72
8x+7y=132
4x+5y=72
(8x+10y)=(144)
8x=-7y+132
8x=-10y+144
-7y+132=-10y+144
3y=12
y=4
4x+20=72
4x=52
x=13
The price for an adult ticket is $13 and the price for a child ticket is $4
Hopes this helps if it doesn’t helps then I am so sorry:
Answer: x^ 9/32
|x| > -1 represents all real numbers.
