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2 years ago

Help me with this please!!!!!!!!!!!!!!

Mathematics

1 answer:

natima [27]2 years ago

5 0

Answer:

sin 60 = opp/hyp = f/(6√2)

f = 6✓2 × sin 60 = 6✓2 × (✓3/2)

= 3✓6

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Answer:

−12s2+11st−2t2

Step-by-step explanation:

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2 years ago

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A metal bar weighs 20 ounces. 93% of the bar is silver.how many ounces of silver are in the bar.

olga55 [171]

Answer:

18.6 ounces

Step-by-step explanation:

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3 years ago

Plz answer with work

V125BC [204]

Answer:

Calculate 93% of 29.96.

Your final answer is approximately 27.86

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2 years ago

The function F represents the revenue in dollars the school can expect to receive if it sells 220-12× coffee mugs for dollars ea

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2 years ago

A corporation must appoint a president, chief executive officer (CEO), chief operating officer (COO), and chief financial off

Yakvenalex [24]

Answer:

a) The officers can be appointed in 24024 different ways.

b) The committee can be appointed in 1001 different ways.

c) 1.1% probability of randomly selecting the committee members and getting the three youngest of the qualified candidates

Step-by-step explanation:

The order in which the officers are appointed is important(the first is the president, second the CEO and so on...). So the permutations formula will be used.

Otherwise, in the committee there are no roles, so the order is not important. So the combinations formula will be used.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

A. How many different ways can the officers be appointed?

4 from a set of 14, with roles. So a permutation.

$P_{(14,4)} = \frac{14!}{(14-4)!} = 24024$

The officers can be appointed in 24024 different ways.

B. How many different ways can the committee be appointed?

4 from a set of 14, without roles. So combination

$C_{14,4} = \frac{14!}{4!(14-4)!} = 1001$

The committee can be appointed in 1001 different ways.

C. What is the probability of randomly selecting the committee members and getting the three youngest of the qualified candidates?

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes.

The three youngest(1 combination), and one of the other 14-3 = 11. So $D = 1*11 = 11$

Total outcomes:

From B., 1001, so $T = 1001$

Probability:

$p = \frac{D}{T} = \frac{11}{1001} = 0.011$

1.1% probability of randomly selecting the committee members and getting the three youngest of the qualified candidates

8 0

3 years ago