Answer:
gay
Suppose we have a simple random sample of 400 households drawn from a city with 40,000 households . A 95% confidence interval estimate for the population mean number of children per household is [1.1,2.3]. Given this, what is the lower confidence limit for the total number of children in the city
Answer:
b=200 and m=200
Step-by-step explanation:
There are many answers to this problem. You can replace b and n for the number 200. You need to find what two numbers, added up, will give you 400. If b=200 and m=200, when added up, it will give you 400.
93 11/16 written as a decimal is 93.6875. Rounded it is approximately 93.7
I hope this helps:)
What do you need help with?
Answer:
-5
Step-by-step explanation:
Once you get y alone the equation will look like this y=-7/4x-5.
The slope intercept form dictates that y=mx+b, with b being the y-intercept, so -5 is b, therefore the y intercept.
