All categories

2 years ago

What is the correct answer to this geometry question?

Mathematics

2 answers:

dsp732 years ago

7 0

Answer:

Step-by-step explanation:

20 = 12 + 16 + 2x

20 - 12 - 16 = 2x

-8 = 2x

x = -4

--------------------------------

check

20 = 12 + 16 + 2*-4

20 = 20

the answer is good

andrezito [222]2 years ago

4 0

HI + IJ = HJ

=> x + 12 + 16 + x = 20

<=> 2x + 28 = 20

<=> 2x = -8

<=> x = -4

with x = -4 => HI = - 4 + 12 = 8

Step-by-step explanation:

You might be interested in

Hi again I’ll appreciate it if you help me

BartSMP [9]

Answer:

answer is in the picture with work, just know your formulas and plug the numbers in and you'll be fine

7 0

2 years ago

What is the square root of 674887473

Hunter-Best [27]

25978.5964401. You can type it in a calculator and get the same answer!(:

6 0

3 years ago

Read 2 more answers

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$