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swat32
3 years ago
5

There is 10 fish in a fish tank and 5 of them drowned how many fish are there?

Mathematics
2 answers:
creativ13 [48]3 years ago
6 0
10 fish are left in the tank
a_sh-v [17]3 years ago
5 0

There are 10 fish and 5 are taken away, that means that the sum we have to do is:

10 - 5

So, 10 - 5 ≈ 5

So there are 5 fish left in the tank.

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Answer:

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Step-by-step explanation:

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If p=1 and q=4, evaluate the following expression:4q−p/p+q​
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Answer:

19

Step-by-step explanation:

This was done the normal way of multiplying and dividing first:

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If you wanted to do the addition and subtraction first, the equation would have been:

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3 years ago
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Help me please numbers 7 and 8
Olegator [25]
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Which of the following graphs best represents the solution to the pair of equations below? y = −x + 6 y = 2x − 3 A coordinate pl
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The lines are 

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4 years ago
A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th
QveST [7]

we know that

the volume of a cone is equal to

V= \frac{1}{3} \pi r^{2}h

in this problem

the radius is equal to

r= \frac{112}{2}= 56ft

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Applying the Pythagorean Theorem find the height

h^{2} = l^{2}-r^{2}

l=65 ft

h^{2} = 65^{2}-56^{2}

h^{2} = 1,089

h=33 ft

2) <u>Find the volume before the storm</u>

V= \frac{1}{3}*\pi* 56^{2}*33

V=34,496\pi\ ft^{3}

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

V= \frac{1}{3}*\pi* (56/3)^{2}*11

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<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

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therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is \frac{1}{27} times the original volume

<u>Part b)</u>  Estimate the number of lane miles that were covered with salt

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6) <u>Find the pounds of road salt used</u>

104,358.59*80=8,348,687.2\ pounds    

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8,348,687.2/350=23,853.39 \ lane\ miles  

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is 23,853.39 \ lane\ miles

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

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1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}

8) <u>Find the pounds of road salt </u>

4,013.79*80=321,103.20\ pounds

9) <u>Find the number of lane miles </u>

321,103.20/350=917.44 \ lane\ miles

therefore

<u>the answer part c) is</u>

the number of lane miles is 917 \ lane\ miles

7 0
4 years ago
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