The question is what numbers satisfy A ∩ C.
The symbol ∩ means intersection, .i.e. you need to find the numbers that belong to both sets A and C. Those numbers might belong to the set C or not, because that is not a restriction.
Then lets find the numbers that belong to both sets, A and C.
Set A: perfect squares from A to 100:
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
9^2 = 81
10^2 = 100
=> A = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}
Set C: perfect fourths
1^4 = 1
2^4 = 16
3^4 = 81
C = {1, 16, 81?
As you see, all the perfect fourths are perfect squares, so the intersection of A and C is completed included in A. this is:
A ∩ C = C or A ∩ C = 1, 16, 81
On the other hand, the perfect cubes are:
1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 81
B = {1, 8, 27, 81}
That means that the numbers 1 and 81 belong to the three sets, A, B, and C.
In the drawing you must place the number 16 inside the region that represents the intersection of A and C only, and the numbers 1 and 81 inside the intersection of the three sets A, B and C.
a + a + a is the same as multiplying a by 3 so you would have 3a
b + b is the same as multiplying b by 2 so you would have 2b
Combing everything together you would have the final answer of :
3a + 2b + c
Answer:
C) $90.48
Step-by-step explanation:
72.39*.2=14.478
72.39*.05=3.6195
14.478+3.6195=18.0975
18.0975+72.39=90.4875
Answer:
The answer for this question is c
Answer:
x = 6
Step-by-step explanation:
2/3=8/x+6
Using cross products
2 * (x+6) = 3*8
2(x+6) = 24
Divide by 2
x+6 =12
Subtract 6
x = 6
