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Kamila [148]
3 years ago
15

A school is holding a carnival and hopes to raise $500. Child tickets cost $3 and adult tickets cost $5. If the school sells x c

hild tickets and y adult tickets, then the equation 3x + 5y = 500 expresses the fact that the school raised exactly $500 from ticket sales.
Mathematics
2 answers:
inn [45]3 years ago
8 0

Answer:

x=100

y=40

Step-by-step explanation:

~ First I made 500 into a number where it can be divisable by 3. 5x40=200

500-200=300, 300 divided by 3 equals 100

olchik [2.2K]3 years ago
6 0

Answer:

zebra

Step-by-step explanation:

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Please answer this correctly
Luba_88 [7]

Answer:

5 and 4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(6 1/3-1/6x 36=?<br> 221/6<br> 216<br> 222<br> 242
scoundrel [369]

Answer:

<em>-(6 1/3-1/6x 36=216</em>

Hope I helped

8 0
3 years ago
Which fraction is equivalent to 1/2 • 4/3 divided by 5/6 ?
Katen [24]

I believe the answer you are looking for is 4/5.

Solution:

1/2 • 4/3=2/3

2/3÷5/6=2/3 • 6/5

4/5

5 0
3 years ago
2 Here are two equations:
MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

6(3) + 4(4) = 34\\18+16=34\\34=34\\

Putting in Equation 2:

5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15

<u>ii. (4,2.5)</u>

Putting in Equation 1:

6(4) + 4(2.5) = 34\\24+10=34\\34=34\\

Putting in Equation 2:

5(4) - 2(2.5) = 15\\20-5 = 15\\15=15

<u>ill. (5,5)</u>

6(5) + 4(5) = 34\\30+20=34\\50\neq 34

Putting in Equation 2:

5(5) - 2(5) = 15\\25-10 = 15\\15=15

<u>iv. (3,2)</u>

6(3) + 4(2) = 34\\18+8=34\\26\neq 34

Putting in Equation 2:

5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

  • brainly.com/question/10534381
  • brainly.com/question/10538663

#LearnwithBrainly

8 0
3 years ago
Show a reciprocal numerical expression for each equation using multiplication, please!
iris [78.8K]
\frac{2}{3}÷ 4 = \frac{2}{3} \times  \frac{1}{4} = \frac{1}{6}

\frac{1}{8}÷ 3 = \frac{1}{8} \times \frac{1}{3} = \frac{1}{24}

\frac{3}{4}÷ 6 = \frac{3}{4} \times \frac{1}{6} = \frac{1}{8}

\frac{1}{36}÷ 2 = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}

4 0
3 years ago
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