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2 years ago

Which statement correctly compares the two functions shown?

Mathematics

1 answer:

krok68 [10]2 years ago

4 0

Answer:

Step-by-step explanation:

For Function 2

x=1 y=8

x=2 y=11

8=m+b

11=2m+b

11-8=2m-m

m=3

8=3+b

b=5

y=3x+5

Function 1

y=4x+5

Function 2

y=3x+5

....................

Function 1 has the same y-intercept and greater slope than Function 2.

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Find the quadratic polynomial if zeros of it are 2 and 1/3 respectively

muminat

Answer:

$\boxed{\sf \ \ \ 3x^2-7x+2 \ \ \ }$

Step-by-step explanation:

Hello,

There are a lot of polynomials which have 2 and 1/3 as zeroes,

I can show you one below

$3(x-2)(x-\dfrac{1}{3})=(x-2)(3x-1)=3x^2-x-6x+2=3x^2-7x+2$

hope this helps

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3 years ago

Zachary final project for a college course took A semester to write and had 95,234 words Zachary wrote 35 ,295 words the first m

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3 years ago

A legal firm offers some services "pro bono", which means that they work for clients free of charge. The legal firm accepted 2%

Alexxandr [17]

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3 years ago

Read 2 more answers

if leah is 6 years old then sue and John is 5 years older than leah and the total of the ages is 41 then how old is sue

lora16 [44]

6+5+x=41 11+x=41 11+-11+x=41+-11 x=30 Sue is 30 years old

7 0

3 years ago

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

3 years ago