Answer:
Chromosome 21 in figure D is the result of a process known as non-disjunction
Explanation:
Meiosis is the process of cell division that serves to obtain gametes, cells with exactly half the chromosome load of the species. This process involves the equal distribution of chromosomes in each daughter cell.
Non-disjunction is an alteration in the separation of the sister chromatids during meiosis, resulting in a gamete with non-separated sister chromatids, which when joined to a normal gamete can produce an organism with an extra chromosome.
In the karyotype shown in the photo, the non-disjunction in chromosome 21 produces a trisomy, a type of aneuploidy seen in Down syndrome.
Learn more:
Trisomy brainly.com/question/484286
Answer:
Like the human body, the bicycle relys on other things to keep moving. For example, in order for the bicycle to keep moving, the rider needs to have legs and be able to push the pedals foreward. In order to breath, the body needs to have lungs and those lungs depend on the heart to pump blood throughout the body. The lungs rely on the heart and your brething relys on your lungs. Hope this helped, brainliest always appreciated.
Explanation:
Baby girls are 4.1mm
Baby boys a 3mm
Answer:
b
dissolving is a chemical change
Answer:
Explanation:
The Genotype of the woman is XCbXN
The man XNY
Since the allele for the color blindness is carried on one of the X -chromosomes of the carrier mother, then the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal allele from the mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal X allele from the father.
Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes
1. XNY vs XCbXN.Then the one of the boys will be colorblind and the one of girls will be carriers. XNXCb, XNXN, XCbY,XNY 50 %
2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle
Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).
The proportions that will be the females since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls take the defective allele from the mothers and take normal from the father,they will all be carriers,since the X of the father is normal.
They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.
