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3 years ago

Which expression concerts 100 inches per minute to feet per minute

Mathematics

1 answer:

Irina18 [472]3 years ago

8 0

Answer:

The third choice, or 100 in/ 1 min × 1 ft/ 12 in.

Step-by-step explanation:

When converting, you want to use the proper units.

When going from inches to feet, note that 1 foot = 12 inches.

100 in/ 1 min × 1 ft/ 12 in

(the inches cancel, and you are left with ft per min.)

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Evaluate 3 – 24 - 8 + 32

UNO [17]

Answer:

Step-by-step explanation:

Evaluate the calculation from left to right, that is

3 - 24 - 8 + 32

= - 21 - 8 + 32

= - 29 + 32

= 3

6 0

3 years ago

Read 2 more answers

A campsite charges $12 per day for the site rental and $8 for parking . The total campsite charge C (in dollars) is given by C=1

Vsevolod [243]

We are given equation of total campsite charge

$C=12d+8$

where

C is total campsite charge C (in dollars)

d is the number of days that the site is rented

so, here we will have

C is y-axis or dependent variable

d is x-axis or independent variable

we can find any two points and then we locate it

after that we can join them to get our graph

At d=0:

$C=12\times 0+8$

$C=8$

so, our point is (0,8)

At C=0:

$0=12d+8$

$-8=12d$

$d=\frac{-2}{3}$

so, our point is $(\frac{-2}{3},0)$

now, we can locate these points and then join it

8 0

3 years ago

Solve for x <br>−42=6(x−6)<br><br>x=

nevsk [136]

Answer:

X= -1

Step-by-step explanation:

So to solve equations like this, you want to isolate the variable first. Then you begin to simplify by dividing each side of the equation by a factor that does not contain a variable.

7 0

3 years ago

there are 12 bottles of water and 15 cans of soda in cooler if you randomly grab one beverage from the cooler is there a probabi

Simora [160]

So 12 waters and 15 sodas makes 27 drinks total for you have a 12/27 chance of grabbing water ad 15/27 on soda<span />

4 0

3 years ago

In order to evaluate 7 sec(θ) dθ, multiply the integrand by sec(θ) + tan(θ) sec(θ) + tan(θ) . 7 sec(θ) dθ = 7 sec(θ) sec(θ) + ta

Maurinko [17]

Answer:

$\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c$

Step-by-step explanation:

The question is not properly formatted. However, the integral of $\int {7 \sec(\theta) } \, d\theta$ is as follows:

$\int {7 \sec(\theta) } \, d\theta$

Remove constant 7 out of the integrand

$\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) } \, d\theta$

Multiply by 1

$\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * 1} \, d\theta$

Express 1 as: $\frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}$

$\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * \frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta$

Expand

$\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta$

Let

$u = \sec(\theta) + \tan(\theta)$

Differentiate

$\frac{du}{d\theta} = \sec(\theta)\tan(\theta) + sec^2(\theta)$

Make $d\theta$ the subject

$d\theta = \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}$

So, we have:

$\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{u}} \,* \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}$

Cancel out $\sec(\theta)\tan(\theta) + sec^2(\theta)$

$\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{1}{u}} \,du}}$

Integrate

$\int {7 \sec(\theta) } \, d\theta = 7\ln(u) + c$

Recall that: $u = \sec(\theta) + \tan(\theta)$

$\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c$

8 0

3 years ago