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Alenkasestr [34]
3 years ago
10

Divide (24w^10+8w^12)/(4w^4)

Mathematics
2 answers:
Lesechka [4]3 years ago
7 0
\bf \cfrac{24w^{10}+8w^{12}}{4w^4}\impliedby \textit{distibuting the denominator}
\\\\\\
\cfrac{24w^{10}}{4w^4}+\cfrac{8w^{12}}{4w^4}\implies 6w^{10}w^{-4}+2w^{12}w^{-4}\implies 6w^{10-4}+2w^{12-4}
\\\\\\
6w^6+2w^8
Alex73 [517]3 years ago
7 0

Answer:

\Rightarrow 6w^6+2w^8

Step-by-step explanation:

Given: \dfrac{24w^{10}+8w^{12}}{4w^4}

We need to divide it

First we factor numerator and denominator and cancel the like factor from top and bottom.

24w^{10}\rightarrow 6\cdot 4\cdot w^{10}

8w^{12}\rightarrow 2\cdot 4\cdot w^{10}\cdot w^2

Now factor the numerator. Take out 4w^{10} common

\Rightarrow \dfrac{4w^{10}(6+2w^2)}{4w^4}

cancel 4 and w^4

\Rightarrow w^{6}(6+2w^2)

We get

\Rightarrow 6w^6+2w^8

Hence, The result of division is \Rightarrow 6w^6+2w^8

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