Question

Divide (24w^10+8w^12)/(4w^4)

Answer 1

$\bf \cfrac{24w^{10}+8w^{12}}{4w^4}\impliedby \textit{distibuting the denominator} \\\\\\ \cfrac{24w^{10}}{4w^4}+\cfrac{8w^{12}}{4w^4}\implies 6w^{10}w^{-4}+2w^{12}w^{-4}\implies 6w^{10-4}+2w^{12-4} \\\\\\ 6w^6+2w^8$

Answer 2

Answer:

$\Rightarrow 6w^6+2w^8$

Step-by-step explanation:

Given: $\dfrac{24w^{10}+8w^{12}}{4w^4}$

We need to divide it

First we factor numerator and denominator and cancel the like factor from top and bottom.

$24w^{10}\rightarrow 6\cdot 4\cdot w^{10}$

$8w^{12}\rightarrow 2\cdot 4\cdot w^{10}\cdot w^2$

Now factor the numerator. Take out $4w^{10}$ common

$\Rightarrow \dfrac{4w^{10}(6+2w^2)}{4w^4}$

cancel 4 and $w^4$

$\Rightarrow w^{6}(6+2w^2)$

We get

$\Rightarrow 6w^6+2w^8$

Hence, The result of division is $\Rightarrow 6w^6+2w^8$