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3 years ago

A store increases the price of a sweater from $20 to $22.

Mathematics

2 answers:

attashe74 [19]3 years ago

7 0

The sweater was increased in price by 10 percent.

Alex3 years ago

4 0

Percent increase : (new number - original number) / (original number)...x 100

(22 - 20) / 20 = 2/20 = 0.1.....0.1 x 100 = 10...so there is a 10% increase

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How would you solve this?

finlep [7]

Answer:the probability that a pensioner catches a flu is 0.3 or $\frac{3}{10}$

Step-by-step explanation:

Data:

a) Pensioners who have had a flu jab = $\frac{3}{5}$

b) Pensioners who did not had a flu jab = 1 - $\frac{3}{5}$ = $\frac{2}{5}$

For the first pair of arrows: a is the probability of the upper arrow and b is the probability of the lower arrow.

If pensioner have had a flu jab, the probability of catching flu is $\frac{1}{30}$

Data:

c) Catching flu = $\frac{1}{30}$

d) Not catching flu = 1 - $\frac{1}{30}$ = $\frac{29}{30}$

The second pair of arrows on the top: Top arrow is c and bottom arrow is d

If pensioner did not have a flu jab, the probability of catching flu is $\frac{7}{10}$

Data:

e) Catching flu = $\frac{7}{10}$

f) Not catching flu = 1 - $\frac{7}{10}$ = $\frac{3}{10}$

The second pair of arrows on the bottom: Top arrow is e and bottom arrow is f.

Q) Probability pensioner catches a flu

P(catches the flu given that he had the flu jab) + P(catches the flu given that he did not have the flu jab)

( $\frac{3}{5}$ x $\frac{1}{30}$ ) + ( $\frac{2}{5}$ x $\frac{7}{10}$ )

= 0.02 + 0.28

= 0.3

Therefore, the probability that a pensioner catches a flu is 0.3 or $\frac{3}{10}$

Keyword: Probability

Learn more about probability at

#LearnwithBrainly

5 0

3 years ago

Help please ❤️ I don’t understand

tigry1 [53]

Answer:

75% of 124 is 93.

Step-by-step explanation:

I hoped this helped ^^

8 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$