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AfilCa [17]
3 years ago
9

Write the first three terms of the sequence n? + 3 Answer quick plzzz

Mathematics
1 answer:
Alborosie3 years ago
6 0

Answer:

3, 6, 9

Step-by-step explanation:

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Kaya devoted 2/5 of her study time to mathematics, 3/20 of her time to social studies, 1/3 of her time to chemistry and the rema
andrezito [222]

Answer:

  54 minutes

Step-by-step explanation:

The sum of fractions is ...

  2/5 + 3/20 + 1/3 = 11/20 +1/3 = (3·11 + 20·1)/(20·3) = 53/60

Then the 42 minutes devoted to English represents 1 - 53/60 = 7/60 of her study time.

Kaya's social studies time is 3/20 = 9/60 of her total, so the ratio of SS to Eng is ...

  SS : Eng = (9/60) : (7/60) = 9 : 7

When we multiply the numbers in this ratio by 6, we find ...

  SS : Eng = 54 : 42

Kaya spent 54 minutes studying social studies.

5 0
3 years ago
Is 43 a composite number
d1i1m1o1n [39]
No.  43 is a prime number.  It has no other factors besides ' 1 ' and itself.
7 0
3 years ago
Read 2 more answers
Dr. Miriam Johnson has been teaching accounting for over 20 years. From her experience, she knows that 60% of her students do ho
oksano4ka [1.4K]

Answer:

a) The probability that a student will do homework regularly and also pass the course = P(H n P) = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P') = 0.12

c) The two events, pass the course and do homework regularly, aren't mutually exclusive. Check Explanation for reasons why.

d) The two events, pass the course and do homework regularly, aren't independent. Check Explanation for reasons why.

Step-by-step explanation:

Let the event that a student does homework regularly be H.

The event that a student passes the course be P.

- 60% of her students do homework regularly

P(H) = 60% = 0.60

- 95% of the students who do their homework regularly generally pass the course

P(P|H) = 95% = 0.95

- She also knows that 85% of her students pass the course.

P(P) = 85% = 0.85

a) The probability that a student will do homework regularly and also pass the course = P(H n P)

The conditional probability of A occurring given that B has occurred, P(A|B), is given as

P(A|B) = P(A n B) ÷ P(B)

And we can write that

P(A n B) = P(A|B) × P(B)

Hence,

P(H n P) = P(P n H) = P(P|H) × P(H) = 0.95 × 0.60 = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P')

From Sets Theory,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

P(H n P) = 0.57 (from (a))

Note also that

P(H) = P(H n P') + P(H n P) (since the events P and P' are mutually exclusive)

0.60 = P(H n P') + 0.57

P(H n P') = 0.60 - 0.57

Also

P(P) = P(H' n P) + P(H n P) (since the events H and H' are mutually exclusive)

0.85 = P(H' n P) + 0.57

P(H' n P) = 0.85 - 0.57 = 0.28

So,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

Becomes

0.03 + 0.28 + 0.57 + P(H' n P') = 1

P(H' n P') = 1 - 0.03 - 0.57 - 0.28 = 0.12

c) Are the events "pass the course" and "do homework regularly" mutually exclusive? Explain.

Two events are said to be mutually exclusive if the two events cannot take place at the same time. The mathematical statement used to confirm the mutual exclusivity of two events A and B is that if A and B are mutually exclusive,

P(A n B) = 0.

But, P(H n P) has been calculated to be 0.57, P(H n P) = 0.57 ≠ 0.

Hence, the two events aren't mutually exclusive.

d. Are the events "pass the course" and "do homework regularly" independent? Explain

Two events are said to be independent of the probabilty of one occurring dowant depend on the probability of the other one occurring. It sis proven mathematically that two events A and B are independent when

P(A|B) = P(A)

P(B|A) = P(B)

P(A n B) = P(A) × P(B)

To check if the events pass the course and do homework regularly are mutually exclusive now.

P(P|H) = 0.95

P(P) = 0.85

P(H|P) = P(P n H) ÷ P(P) = 0.57 ÷ 0.85 = 0.671

P(H) = 0.60

P(H n P) = P(P n H)

P(P|H) = 0.95 ≠ 0.85 = P(P)

P(H|P) = 0.671 ≠ 0.60 = P(H)

P(P)×P(H) = 0.85 × 0.60 = 0.51 ≠ 0.57 = P(P n H)

None of the conditions is satisfied, hence, we can conclude that the two events are not independent.

Hope this Helps!!!

7 0
3 years ago
You and a friend are buying lemons and sugar for a lemonade stand. You spend ​$14.45 to buy lemons and your friend spends ​$8.85
enot [183]

Answer:

23.3

Step-by-step explanation:

8 0
3 years ago
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A classroom has 4 new boxes of chalk and 6 individual pieces of chalk in use. How many total pieces of chalk are in the classroo
AveGali [126]
The total number of pieces of chalk in the classroom will be the number of pieces in the 4 boxes in addition to the six individual pieces.

The average box of chalk holds 12 pieces of chalk
This means that 4 boxes have 12*4 = 48 pieces

Total number of pieces = 48 + 6 = 54 pieces of chalk
8 0
3 years ago
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