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2 years ago

Karrem says that the ratio 4:1 is eqivilent to the ratio of 12:9 because 4+8=12 and 1+8 =9 is karreem correct

Mathematics

1 answer:

Mariana [72]2 years ago

8 0

Answer:

No, Kareem is incorrect.

Step-by-step explanation:

Kareem says that the ratio of $\frac{4}{1}=\frac{12}{9}$ because 4 + 8 = 12 and 1 + 8 = 9

But the correct way to rewrite the ratio 4 : 1 is,

$\frac{4}{1}=\frac{4\times 3}{1\times 3}$

Which becomes as,

$\frac{4}{1}=\frac{12}{3}$

Therefore, Kareem is not correct.

Correct ratio equivalent to 4 : 1 is 12 : 3.

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A building contractor is to dig a foundation 30 feet long, 12 feet wide, and 6 feet deep. The contractor pays $20 per load fo

kogti [31]

Answer:

$1800

Step-by-step explanation:

Volume of the foundation: 30*12*6 = 2160 cubic feet

we need to convert this into yards because a truckload is 8 cubic yards, 2160/3 = 720 cubic yd

One truckload is 8 cubic yards

# of truckloads needed: 720/8 = 90 truckloads

Cost: $20*90 = $1800

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3 years ago

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Find all values of x for which the series converges. (enter your answer using interval notation. ) [infinity] (4x)n n = 1

andreyandreev [35.5K]

The series converges to 1/(1-9x) for -1/9<x<1/9

Given the series is ∑ $9x^{n} x^{n}$

We have to find the values of x for which the series converges.

We know,

∑ $ar^{n-1}$ converges to (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, ∑ $(9x)^{n}$ is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for -1/9<x<1/9

And geometric series converges to a/(1-r)

Here, a = 1 and r = 9x

Therefore, a/(1-r) = 1/(1-9x)

Hence, the given series converges to 1/1-9x for -1/9<x<1/9

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1 year ago

The heights in inches, of some small trees for sale at a garden store are 62, 62, 59, 61, 59, 70, 59, and 62. What is the median

Nana76 [90]

Answer:

Step-by-step explanation:

the mean height, remember is the average

62+62+59+61+59+70+59+62=494/8=61.75

median is the middle value, so we will write the numbers in order

59,59,59,61,62,62,62,70

we have an even number so we add the middle numbers and divide by 2,

the median=61+62=123/2=61.50

mode is the number that occurs most often : 62 and 59

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2 years ago

15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.

Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = $30C5 = \frac{30 !}{(30-5)!5!} \\$

$30C5 = 142506$ ways

Number of ways of selecting 5 good bulbs from 26 bulbs = $26C5 = \frac{26 !}{(26-5)!5!} \\$

$26C5 = 65780$ ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = $\frac{26C4 * 4C1}{30C5}$

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) = $\frac{26C3 * 4C2}{30C5}$

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) + Pr(2 defective) + Pr(3 defective) + Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) = $\frac{26C2 * 4C3}{30C5}$

Pr(3 defective) = 0.009

Pr(4 defective) = $\frac{26C1 * 4C4}{30C5}$

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

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3 years ago