3) The height of an object that is thrown straight up from a height of 6 feet
1 answer:
Answer:
- 44 feets
Step-by-step explanation:
Given the model:
h(t) = -15t2 + 25t + 6
Average height of object from 1 - 4 seconds
At :
t = 1
h(1) = -15(1)^2 + 25(1) + 6 = 16 feets
t = 2
h(2) = -15(2)^2 + 25(2) + 6 = - 4 feets
t = 3
h(3) = -15(3)^2 + 25(3) + 6 = - 54 feets
t = 4
h(4) = -15(4)^2 + 25(4) + 6 = -134 feets
Average height:
(16 + (-4) + (-54) + (-134)) / 4 feets = (- 176 / 4) feets
= - 44 feets
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