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podryga [215]
3 years ago
5

Help!! 20 points and brainly!!

Mathematics
2 answers:
igomit [66]3 years ago
8 0
Let the consecutive integers be x, x+1 and x+2.
By the question,
x+x+1+x+2 = 84
Or, 3x+3 = 84
Or, 3(x+1) = 84
Or, x+1 = 84/3
Or, x+1 = 28
Or, x= 28-1
.•. x= 27,,

Hence the smallest integer is 27,,
sergejj [24]3 years ago
5 0

Answer:

26

Step-by-step explanation:

Let x be the first even integer

x+2 is the second even integer

x+4  is the third even integer

The sum of three consecutive even integers is 84

x+ (x+2) + (x+4) =84

Combine like terms

3x +6 = 84

Subtract 6 from each side

3x+6-6 =84-6

3x =78

Divide each side by 3

3x/3 = 78/3

x =26

The three integers are 26, 28,30

The smallest is 26

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Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

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P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
3 years ago
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