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GrogVix [38]
3 years ago
5

Solve -3x - y = 8 - 7x + 3y = -24

Mathematics
2 answers:
Nookie1986 [14]3 years ago
7 0
The solution is (0,-8)
My name is Ann [436]3 years ago
3 0

Answer:

1.x1=49.5 or x2=-48.5

Step-by-step explanation:

=-3x-y-8=8-8

=-3x-y-8=0 --> a=-3 b=-1 c=-8

solve it using quadratic formula

=-(-1)±√(-1)^2-4(-3)(-8)/2

= 1±√2+96/2

=1±√98/2

=1+98/2 ----> x1=49.5

=1-98/2 -----> x2=-48.5

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salantis [7]
Hello,

A linear function is a polynomial function of degree 1
(1,2,3,4,5,6,....)
A quadratic function is a polynomial function of degree 2
(1,4,9,16,25,49,64,81,...)
A exponential function is not a polynomial function (we may imagine a infinity degree)
(1,2,4,8,16,32,64,128,256,512,1024,...)



3 0
3 years ago
Use the substitution method to solve each linear system. 4x - 3y = -13,-2x + y = 4
alisha [4.7K]

Answer:

Step-by-step explanation:

(X,Y)=(-55/2,-38

6 0
3 years ago
What is 89,659rounding to the nearest hundred thousand
algol [13]
89,659 rounded to the nearest hundred thousand = 100,000
3 0
3 years ago
o check the effect of cold temperature on the elasticity of two brands of rubber bands, one box of Brand A and one box of Brand
const2013 [10]

Answer:

No this is a not good experimental design

Step-by-step explanation:

In an experiment, we seek to establish cause an effect relationship. The effect of one variable on another is examined while keeping other variables constant. A control often establishes the validity of the experiment.

Now the ten rubber bands were selected at random from each box. The experimental group was put in a freezer while the control group was maintained at room temperature.

Comparison of the mean stretch before breakage of the rubber bands in both groups establishes the effect of cold temperature on elasticity of rubber bands.

However, this is not a good experimental design because the sample rubber bands should have been picked from different boxes of brand A and B and not from the same box.

Secondly, samples from the two brands should have been put in the freezer and kept at room temperature. That is, ten rubber bands from A are put on the freezer and another 10 are left at room temperature. 10 rubber bands from B are put in the freezer and another 10 are left at room temperature.

The mean elasticity of the both groups can now be meaningfully compared from the data obtained.

3 0
3 years ago
The normal monthly precipitation (in inches) for August is listed for 20 different U.S. cities. Find the mean of the data. 3.5 1
Burka [1]

Answer:

The correct answer is 2.94 in.

Step-by-step explanation:

The monthly precipitation for August in 20 different U.S. cities are observed in inches.

The data is given by: 3.5, 1.6, 2.4, 3.7, 4.1, 3.9, 1.0, 3.6, 4.2, 3.4, 3.7, 2.2, 1.5, 4.2, 3.4, 2.7, 0.4, 3.7, 2.0 and 3.6.

We intend to find the mean of the given data.

Therefore mean of the precipitation is ∑data ÷ 20 = \frac{58.8}{20} = 2.94 inches.

Thus the mean of the data is 2.94 inches.

5 0
3 years ago
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