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3 years ago

Is the product of 2/5 and 5 greater than or less than 2/5 is it greater than or less than 5

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

It is greater than 2/5 greater than 5 and and 5 greater than 2/5

vlabodo [156]3 years ago

5 0

A great way to figure this out is to actually multiply it. 2/5 x 5/1 You can simplify numbers diagonally, so the two fives can both cancel out into ones. now we have 2/1 x 1/1, which is the same as 2x1 This equals 2, which is less than five.
One great thing to know is that anything multiplied by a number less than one (a fraction or a decimal) will always be smaller than the original number.

Answer: 2
Hope this helped!! (:

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Will mark the Brainliest !!!!! A team of 5 boys and 4 girls will be chosen from a group of 16 boys and 13 girls,

vfiekz [6]

Answer:

Step-by-step explanation:

The total number of permutations of boys and girls on the team are:

¹⁶P₅*¹³P₄

Bob will be one of the fixed boys to be picked. Hence, actually 4 boys are to be picked from 15. The permutations of girls being picked remains the same.

Probability = Permutations with Bob as one of the boys / Total permutations

Probability = (¹⁵P₄*¹³P₄) / (¹⁶P₅*¹³P₄) = ¹⁵P₄ / ¹⁶P₅

Probability = $\frac{15!}{(15-4)!}/\frac{16!}{(16-5)!}$ = 15! / 16! = 1/16

Now, Bob is one of the fixed boys and Jane is one of the fixed girls. Hence, actually 4 boys are to be picked from 15 and 3 girls are to be picked from 12.

Probability = Permutations with bob as one of the boys and jane as one of the girls / Total permutations

Probability = (¹⁵P₄*¹²P₃) / (¹⁶P₅*¹³P₄) = (1/16)*(1/13) = 1/208

Now, the probability that at least Jane or Bob will be picked has been asked. This probability is a combination of three probabilities:

Probability = (Probability that only Bob will be picked) + (Probability that only Jane will be picked) + (Probability that both will be picked)

Probability = 1/16 + 1/13 + 1/208 = 0.123

Total teams possible = ¹⁶P₅*¹³P₄ = 8994585600 teams are possible

5 0

3 years ago

Find the equation of the sphere in standard form centered at (−6,10,5) with radius 5.

Dovator [93]

Answer:

The equation of the sphere in standard form is

$x^{2} +y^{2}+z^{2} +12 x-20 y-10 z+136=0$

Step-by-step explanation:

<u>Step 1</u>:-

The equation of the sphere having center and radius is

$(x-h)^{2} +(y-k)^{2} +(z-l)^{2} = r^{2}$

Given centered of the sphere is (-6,10,5) and radius r=5

$(x-(-6))^{2} +(y-10)^{2} +(z-5)^{2} = 5^{2}$

on simplification,we get

$using (a+b)^{2} =a^{2} +2 a b+b^{2}$

$using (a-b)^{2} =a^{2} -2 a b+b^{2}$

simplify , we get

$x^{2} +y^{2}+z^{2} +12 x-20 y-10 z+136=0$

8 0

3 years ago

Using what you have learned about solving systems of equations, find the number that represents the apple, banana, and cherry.

erica [24]

it would be convenient if you actually give us the equation

8 0

3 years ago

If a monopolist supplies goods at a price; P = 170 - Q, with marginal cost; MC = 52. Find the quantity and price

Arada [10]

Answer:

Quantity = 59 units

Price = $111

Step-by-step explanation:

The Demand function is given by

$P = 170 - Q$

The Marginal cost is given by

$MC = 52$

We are asked to find the quantity and price of goods.

Firstly, obtain the Marginal revenue function from the demand function

The Total revenue is given by

$TR = P \times Q \\\\TR = (170 - Q) \times Q \\\\TR = 170Q - Q^2$

The Marginal revenue is the derivative of the Total revenue,

$MR = \frac{d}{dQ} (TR) = 170Q - Q^2 \\\\MR = \frac{d}{dQ} (TR) = 170 - 2Q \\\\$

Assuming that the monopolist maximizes profits,

$MR = MC \\\\170 - 2Q = 52\\\\2Q = 170 - 52\\\\2Q = 118\\\\Q = 118/2\\\\Q = 59$

Therefore, the quantity is 59 units.

The price of each good is

$P = 170 - Q \\\\P = 170 - 59 \\\\P = 111$

Therefore, the price is $111.

3 0

3 years ago

Please Help!<br> Please write a sentence or more about the difference between each plot

topjm [15]

Box Plot has less variability in the data. We can determine this by the distances between the beginning of the data to the end (range) and the distances between lower quartile and the upper quartile (interquartile range).

Box #1
Range - 30
IQR - 15

Box #2
Range - approximately 23
IQR - approximately 9

Box #2 has less variation in the data because the distances between these 2 ranges are smaller meaning the data is closer together.

6 0

3 years ago