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Elza [17]
3 years ago
5

What is the value of the sin3x/6x; as x approaches to zero

Mathematics
1 answer:
nikklg [1K]3 years ago
6 0

Step-by-step explanation:

When x = 0,

sin3x / 6x = 0 / 0, which is an indeterminate form.

Hence we use L'Hospital's rule:

d/dx (sin3x) = 3cos3x

d/dx (6x) = 6

Now we have 3cos3x / 6 or 0.5cos3x.

When x = 0, 0.5cos3x = 0.5(1) = 0.5.

Hence the limit is 0.5.

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Explain how you can find the missing number in 3 4/5 divided by ( blank) equals 2 5/7.
skad [1K]
First make fractions.
2 5/7 = 19/7
3 4/5 = 19/5

19/7*x=19/5
Multiply 7 to other side (7*19/5=133/5)
Multiply 5 to other side (5*19=95)
95x=133
133 divided by 95 yields 1.4

The answer is 1.4
6 0
3 years ago
What is the answer to: − 2 − 1 3 . 8 = − 8 − ( 6 + 1 )?
Elza [17]
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7 0
2 years ago
Show that cos2x=cosx
PSYCHO15rus [73]

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factor

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using the zero product property

2 cos x+1 =0    cos x -1 =0

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taking the arccos of each side

arccos cos x = arccos (-1/2)         arccos cos x = arccos 1

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remember you get 2 values ( 2nd and 3rd quadrant)

these are the principal values

now we need to add 360

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3 0
3 years ago
Find the slope of the line passing through the points (-4, -2) and (6, -2).
Tems11 [23]

Answer: (-4, -2) and (6, -2)'s slope is 0, (2,9) and (2, -5)'s is undefined

Step-by-step explanation:

bro its not that hard, y1-y2 divided by x1-x2

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k0ka [10]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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